Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:
1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.
The total walkway area is thus x^2 + 4(2^2) + 4(x*2).
We want to find the dimensions of the garden. To do this, we need to find the value of x.
Let's sum up the garden dimensions and the walkway dimensions:
x^2 + 4(2^2) + 4(x*2) = 196 sq ft
x^2 + 16 + 8x = 196 sq ft
x^2 + 8x - 180 = 0
(x-10(x+18) = 0
x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.
The garden dimensions are (10 feet)^2, or 100 square feet.
Answer:
Step-by-step explanation:
They are equal. When the negative sign is inside the box the absolute value is positive, when the negative sign is outside the box THEN it is negative.
F(t)
= t2 + 4t − 14
y + 14 + 4 = (
t2 + 4t +4)
y + 18 = ( t +
2)^2
so the vertex
of the parabola is ( -2 , -18)
<span>the axis of
symmetry is y = -18</span>
Step-by-step explanation:
z-score of X = 6150
z-score of X = 6350
P(X<6150) + P(X>6350)
=P(z<-0.4) + P(z>-0.4)
=0.3446+0.3446
=0.6892
The answer is 80, because 8 is in the hundreds place which means 80.
