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PIT_PIT [208]
3 years ago
10

Find the value of h(x) = -3x – 12 when x = -2? Show work

Mathematics
1 answer:
7nadin3 [17]3 years ago
7 0

Answer:

-6

Step-by-step explanation:

h(x) = -3x – 12 becomes h(-2) =  -3(-2) – 12 = -6

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Factor the binomial.<br> 4z2 − 25<br> 4z2 − 25 =
svetoff [14.1K]

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6 0
2 years ago
I Prove that Cos(90-θ)/1+sin(90-θ) +1+sin(90-θ) /cos(90-θ) =2
USPshnik [31]
Okay,

so first you gotta know that cos(90-x) is equal to sinx and sin(90-x) is equal to cosx!!
Now all you gotta do is replace the cos(90-x) to sinx in the numerator and sin(90-x) to cosx in the denomenator inorder to make the numerator all into sin and denomenator all into cos.
After that, open up the brackets and solve...
At the end you'll hopefully get something like this :( 1+sin90 ÷ 1+cos90 )
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Hope this helped!  :)
6 0
3 years ago
Read 2 more answers
Write a polynomial function in standard form with zeros at 0, 1, and 2.
Nikitich [7]

Answer:

the first one is correct

6 0
3 years ago
Part B: In complete sentences, explain how a circle can be used to find the circumcenter of the triangle graphed below.
Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

<u><em>Part B:</em></u>

The center of the circumscribed circle around a triangle is equidistant from vertices of that triangle. To find the circumcenter need to draw at least two perpendicular bisectors to the sides of the given triangle. Point of intersect of them is center of the circumscribed circle.

<u><em>Part C:</em></u>

Coordinates of the midpoint of line BC ( y = - 1 ) are

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Because BC is ║ to x-axis and m∠A is 90° , the center of the circle is midpoint of BC and r = \frac{BC}{2} = 4

3 0
2 years ago
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ziro4ka [17]
Five months
Reason: graph y=35.75x+75 and y=17.95x+164 and they connect in the middle of 253-254 for month 5
8 0
3 years ago
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