Okay,
so first you gotta know that cos(90-x) is equal to sinx and sin(90-x) is equal to cosx!!
Now all you gotta do is replace the cos(90-x) to sinx in the numerator and sin(90-x) to cosx in the denomenator inorder to make the numerator all into sin and denomenator all into cos.
After that, open up the brackets and solve...
At the end you'll hopefully get something like this :( 1+sin90 ÷ 1+cos90 )
And since sin90 is 1 (put it in the calculator!) and cos90 is 0, you'll get 2÷1 which is equals to 2!!
Hope this helped! :)
Answer:
Step-by-step explanation:
<u><em>Part B:</em></u>
The center of the circumscribed circle around a triangle is equidistant from vertices of that triangle. To find the circumcenter need to draw at least two perpendicular bisectors to the sides of the given triangle. Point of intersect of them is center of the circumscribed circle.
<u><em>Part C:</em></u>
Coordinates of the midpoint of line BC ( y = - 1 ) are
(
,
) = <em>( - 2 , - 1 )</em> and the equation of the line ⊥ to BC is <em>x = - 2</em>
Because BC is ║ to x-axis and m∠A is 90° , the center of the circle is midpoint of BC and r =
= 4
Five months
Reason: graph y=35.75x+75 and y=17.95x+164 and they connect in the middle of 253-254 for month 5