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devlian [24]
2 years ago
8

A shipping company selects 75 random packages to check their weight.It finds that 3 packages were weighed incorrectly. How many

packages out of 3000 should the company predict have an incorrect weight?
Mathematics
1 answer:
Misha Larkins [42]2 years ago
7 0

Answer: 120 Packages

Step-by-step explanation:

Given

75 random packages are check

3 package is found faulty

So, the percentage of error is

\Rightarrow \dfrac{3}{75}\times 100=4\%

i.e. 4% packages is faulty

For 3000 sample, expected faulty packages are

\Rightarrow 3000\times \dfrac{4}{100}=120\ \text{Packages}

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iren [92.7K]

Answer:

n = 7

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Step-by-step explanation:

4n+6 = n²-15

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n² - 4n - 21 = 0

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n = 7

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7 0
2 years ago
4535 divided by 83 = R =
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Answer:

54 R 53

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Step-by-step explanation:

4535 divided by 83 equals

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2 years ago
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Likurg_2 [28]

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2 years ago
The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p
VLD [36.1K]

Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

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We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

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Chi square critical value for upper tail =

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80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

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Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0
3 years ago
Please help it is easy. i just dont get it. you get extra points for this question
Igoryamba
2,3,7,and 5 are the factors 
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3 years ago
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