Pls help will give brainliest
2 answers:
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Answer:
It is continuous since
Step-by-step explanation:
We are given that the function is defined as follows and
and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity) x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all
. So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that
(this is the definition of continuity at x=0)
Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that
. This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.
Note that when x>0, we have that f(x) = 9+12x. In this case, we have that
. As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.
Thus, , so by definition, f is continuous at x=0, hence continuous over the interval [-4,5].
Answer:
Example: 2/3 + 4/6 + 5/12
Step-by-step explanation:
First find the least common multiple.
2*
2, 4, 6,8, 10. 12, 14, 16, 18, 20
6*
6, 12, 18, 24, 30, 36, 42, 48
12*
12, 24, 36, 48, 60, 74
the least common multiple all three denominators share is -12-
*Evaluate*
2/3 = 8/12
2 times 4 is 8
3 times 4 is 12
*whatever you do to the top you do to the bottom*
