I don't understand how to do this
1 answer:
You might be interested in
Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), 
and 
are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
Now that we have our quadratic function, we are going to use the average formula:
is the function evaluated at the <span>9th month
</span>
is the function evaluated at the 3rd month
![m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}](https://tex.z-dn.net/?f=m%3D%20%5Cfrac%7B%5B9%5E%7B2%7D-24%289%29%2B108%5D-%5B3%5E%7B2%7D-24%283%29%2B108%5D%7D%7B9-3%7D%20)
We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: <span>B. −11.63 dollars per month.</span>
Now that we have our quadratic function, we are going to use the average formula:
</span>
We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: <span>B. −11.63 dollars per month.</span>
Check the picture below.
now, we know that the slanted legs are congruent, since it's an isosceles trapezoid, we also know that the bases are the parallel sides, so, the "altitude" or distance from those bases are the same length, for each of those triangles in the picture.
now, the bases are parallel, that means the altitude segment is perpendicular to the base, the longest side at the bottom, so, we end up with a right-triangle that has a Hypotenuse and a Leg, equal to the other triangle's.
thus, by the HL theorem for right triangles, both of those triangles are congruent, and if the triangles are congruent, all their sides are also, including the ones on the base.
now, we know that the slanted legs are congruent, since it's an isosceles trapezoid, we also know that the bases are the parallel sides, so, the "altitude" or distance from those bases are the same length, for each of those triangles in the picture.
now, the bases are parallel, that means the altitude segment is perpendicular to the base, the longest side at the bottom, so, we end up with a right-triangle that has a Hypotenuse and a Leg, equal to the other triangle's.
thus, by the HL theorem for right triangles, both of those triangles are congruent, and if the triangles are congruent, all their sides are also, including the ones on the base.