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Svetllana [295]
3 years ago
11

Number of protons in uranium 340

Chemistry
2 answers:
Lostsunrise [7]3 years ago
7 0

Answer:

92

Explanation:

because it is the 92nd element on the table it has 92 protons

BlackZzzverrR [31]3 years ago
3 0

Answer:

it is 92

Explanation:

Atomic Mass 238.029 atomic mass units

Number of Protons 92

Number of Neutrons 146

Number of Electrons 92

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In the pie chart below, which of the following represents the amount of Earth's water located in the oceans?
Andrew [12]

Answer:

D. 97%

Explanation:

♪\(*^▽^*)/\(*^▽^*)/

4 0
3 years ago
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Un átomo X posee 29 protones y de carga +2 ¿Cuántos electrones tiene?
lesya [120]

Responder:

27

Explicación:

Dado que:

Número de protones en el átomo X = 29

Carga en el átomo X = +2

Si no hay cargo neto;

número de protones = número de electrones

Sin embargo, dado que el átomo X tiene una carga de +2 (dando 2 electrones).

Por lo tanto,

Número de electrones = número de protones - número de carga en el átomo)

Número de electrones = (29 - 2) = 27

4 0
3 years ago
Question 14 A student dissolves 1.5g of styrene C8H8 in 225.mL of a solvent with a density of 1.02/gmL . The student notices tha
Yuki888 [10]

We must to know:

Cm = molarity = niu / Vs, when the niu = no. of moles and Vs = Volume of solution

the no. niu = mass / molecular mass of substance

molecular mass of C8H8 = 12x8+8x1 = 104 g/mol

=> niu = 1,5 / 104 = 0,0144 moles C8H8

=> Cm = 0,0144/0,225 = 0,06 mol/L

Cmm = molality = niu (C8H8) / mass of solvent (kg)

=> p = mass / V => mass (solvent) = p x V

=> 225 x 1,02 = 229,5 g solvent = 0,2295 kg solvent

=> Cmm = 0,0144 / 0,229,5 = 0,063

8 0
3 years ago
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The second-order rate constants for the reaction of oxygen atoms witharomatic hydrocarbons have been measured (R. Atkinson and J
Pepsi [2]

Answer:

A = 1,13x10¹⁰

Ea = 16,7 kJ/mol

Explanation:

Using Arrhenius law:

ln k = -Ea/R × 1/T + ln(A)

You can graph ln rate constant in x vs 1/T in y to obtain slope: -Ea/R and intercept is ln(A).

Using the values you will obtain:

y = -2006,9 x +23,147

As R = 8,314472x10⁻³ kJ/molK:

-Ea/8,314472x10⁻³ kJ/molK = -2006,9 K⁻¹

<em>Ea = 16,7 kJ/mol</em>

Pre-exponential factor is:

ln A = 23,147

A = e^23,147

<em>A = 1,13x10¹⁰</em>

<em></em>

I hope it helps!

6 0
3 years ago
Balance the following equation:<br> C7H602 + 02 -- CO2 + H20
azamat

Answer:

Explanation:

2C7H6O2 + 15O2 → 14CO2 + 6H2O.

5 0
3 years ago
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