In this question, the <span>patient needs to be given exactly 500 ml of a 5.0%. The content of the glucose should be:
</span>weight= volume * density* concentration<span>
500ml * 1mg/ml *5%= 25mg.
The </span><span>stock solution is 35%, then the amount needed in ml would be:
weight= volume * density* concentration
25mg= volume * 1mg/ml *35%
volume= 25/35%= 500/7= 71.43ml</span>
No, they don't behave similarly since in aromatic hydrocarbons, the electron density is uniform whereas in cyclic alkenes, electron density is not uniform
Answer:
2Na(s) + 2HCl(aq) —> 2NaCl(aq) + H2(g)
Explanation:
Na(s) + HCl(aq) —> NaCl(aq) + H2(g)
Writing an ionic equation will actually help us to understand the equation and also to balance it. This is illustrated below:
Na + H+Cl-
Na is higher than H in the activity series and as such, it will displaces H from the solution and form NaCl with H2 liberated as shown below
Na + H+Cl- —> Na+Cl- + H2
Now, put 2 in front of Na, H+Cl- and Na+Cl- to balance the equation as shown below:
2Na + 2H+Cl- —> 2Na+Cl- + H2
Now we can write the elemental equation as follow:
2Na(s) + 2HCl(aq) —> 2NaCl(aq) + H2(g)
It means it’s neutrally charged! Protons are positive while electrons are negative, so they balance each other out. Neutrons are neutral so they don’t weigh in.
4, 3, 1
Explanation:
Sb has four on the right, so it needs four on the left. It's all alone, so <u>4</u>.
O2 comes in pairs, so you only need <u>3</u> of those to get six oxygens.
And 1 is the place holder for the right side since we got the left to match perfectly.
