Answer:
u-shaped; y-intercept (0,6); symmetrical with respect to the y-axis
Step-by-step explanation:
Given that y = 2x² + 6
The graph would be the shape of that of a parabola. It can be u shaped or n shaped depending on the value of the coefficient of a comparing with the standard equation y = ax² + bx + c. If a > 0, it is u shape and if a < 0, it is n shape.
For this question, since a > 0 it would be u shaped and the intercept can be gotten by putting x = 0.
Therefore y = 0² + 6 = 0
The intercept is at (0,6) and is symmetrical with respect to the y-axis
F(-5) = -5^2 - 2*(-5) - 7 = 25 - (-10) - 7 = 25 + 10 - 7 = 25 + 3 = 28
<span>This is the equation made from the problem where x=mystery number
</span><span>2x+3(x+1)=4(x-1)</span><span>
</span><span>Now let's solve for x!
</span><span>
</span><span>We start by distributing 3 into (X+1)
</span><span>
</span><span>3(x)=3x and 3(1)=3
</span><span>
</span><span>Now our equation is 2x+3x+3=4(x-1)
</span><span>
</span><span>Let's combine both x values on the left side of the equation: 2x + 3x=5x
</span><span>
</span><span>We now have 5x+3=4(x-1)
</span><span>
</span><span>Let's distribute 4 into (x-1)
</span><span>
</span><span>4(x)=4x and 4(-1)=-4
</span><span>
</span><span>Now our equation is 5x+3=4x-4
</span><span>
</span><span>subtract 3 form both sides
</span><span>
</span><span>5x=4x-7
</span><span>
</span><span>subtract 4x from both sides
</span><span>
</span><span>x=-7
</span><span>
</span><span>Yay! So the number she is thinking of is -7!</span><span>
</span>
The final equation is:
Further explanation:
The general form of equation of a line in slope-intercept form is:
Here m is the slope
Given
m=1
(x,y) = (-7,-4)
To find the value of b, we have to put the point in the equation
The final equation is:
Keywords: Slope-intercept form, equation of line
Learn more about slope-intercept form at:
#LearnwithBrainly
Answer:
F, J, K
Step-by-step explanation:
The other choices are regarded as expressions not equations, in which you can find the value of the the given variable.
