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3 years ago

Use the drop-down menus to complete the statement about the inequality m ≥ 2.

Mathematics

1 answer:

Setler79 [48]3 years ago

4 0

Answer:

The inequality m ≥ 2 has infinity many solutions because 2 and any number to the right of 2 on the number line can be substituted for m to make this inequality true.

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What is the solution set of the following equation? 1/5x^2=x-4/5

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I think the answer might be x=4/8

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Patients come into a medical clinic have a mean weight of 207.6 pounds with a standard deviation of 22.6 pounds. the distributio

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3 years ago

Mrs. Miller sells a house for 179,000. If she earns a commission of 6%, how much money does she earn? ( can u also show me how u

Kryger [21]

Hi there!

Mrs. Miller earns a commission of 6% of 179,000

The word "of" is the same thing as a multiplication sign.

6% of 179,000 = 6% × 179,000

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Your answer is: Mrs. Miller earns $10,740 of commission.

There you go! I really hope this helped, if there's anything just let me know! :)

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3 years ago

Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths. X2 y2 − 2x 2y −

Colt1911 [192]

Circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

<h3>What is the equation of circle?</h3>

The equation of the circle is the equation which is used to represent the circle in the algebraic equation form with the value of center point in the coordinate plane and measure of radius.

The standard form of the equation of the circle can be given as,

$(x-h)^2+(y-k)^2=r^2$

Here (h,k) is the center of the circle and (r) is the radius of the circle.

Lets arrange the first equation, in standard form of equation of circle as,

$x^2 +y^2 - 2x+ 2y -1 = 0 \\(x^2 - 2x) +(y^2+ 2y )= 1\\(x^2 - 2x+1) +(y^2+ 2y +1)= 1+1+1\\(x-1)^2+(y+1)^2=(\sqrt{3})^2$

The radius of this circle is √(3).

Lets arrange the second equation, in standard form of equation of circle as,

$x^2 +y^2 - 4x+ 4y - 10 = 0 \\(x^2 - 4x) +(y^2+ 4y )= 10\\(x^2 - 4x+4) +(y^2+ 4y +4)= 10+4+4\\(x-2)^2+(y+2)^2=(\sqrt{18})^2$

The radius of this circle is √(18).

Lets arrange the third equation, in standard form of equation of circle as,

$x^2 +y^2 - 8x - 6y - 20 = 0 \\(x^2 - 8x) +(y^2-6y )= 20\\(x^2 - 8x+16) +(y^2- 6y +9)= 10+16+9\\(x-4)^2+(y-3)^2=(\sqrt{45})^2$

The radius of this circle is √(45).

Similarly, radius of the forth, fifth, sixth and seventh circle is √(23), √(5), √(117) and √(46) units.

Hence, the circles (represented by their equations in general form) in ascending order of their radius lengths can be arranged as first-fifth-second-forth-third-seventh-sixth.

Learn more about the equation of circle here;

brainly.com/question/1506955

3 0

2 years ago

Read 2 more answers