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3 years ago

Increase 250ml by 86%

1 answer:

6 0

250=100%
25=10%
12.5=5%
2.5=1%
25*8=200(80%)
12.5+2.5=15(6%)
200+12=215(86%)
250+200=450(186%)
so 450ml is your answer
Hope this helped :)

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3 years ago

Read 2 more answers

1. Solve: 6x - 12 < 6<br> 2. Solve: 2(3x-8) >8

8090 [49]

Answer:

Step-by-step explanation:

1. here you go mate

step 1

6x - 12 < 6 equation

step 2

6x - 12 < 6 simplify

6x-12+12<6+12

step 3

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answer

x<3

2. Here you go mate

step 1

2(3x-8) >8 equation

step 2

2(3x-8) >8 simplify

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step 3

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3 years ago

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

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3 years ago

If EF = 2x+13, FG = 20, and EG = 71 what's the value of x

klemol [59]

Answer:

Step-by-step explanation:

|<----------------- 71 ----------------------->|

E-----------------------F---------------------G

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EF + FG = DG

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3 years ago

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stiks02 [169]

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<h3>How to work with Pythagoras Theorem?</h3>

From the definitions of trigonometric ratios, we know that;

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Read more about Pythagoras Theorem at; brainly.com/question/27572671

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2 years ago