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Identify the products formed in this Brønsted-Lowry reaction.<br><br> HPO2−4+NO−2↽−−⇀acid+base

klemol [59]

Answer: The products formed in this Bronsted-Lowry reaction are $HNO_{2}$ and $PO^{2-}_{4}$ .

Explanation:

According to Bronsted-Lowry, acids are the species which donate hydrogen ions to another specie in a chemical reaction.

Bases are the species which accept a hydrogen ion upon chemical reaction.

For example, $HPO^{2-}_{4} + NO^{-}_{2} \rightleftharpoons HNO_{2} + PO^{2-}_{4}$

Here, the products formed in this Bronsted-Lowry reaction are $HNO_{2}$ and $PO^{2-}_{4}$ .

Thus, we can conclude that the products formed in this Bronsted-Lowry reaction are $HNO_{2}$ and $PO^{2-}_{4}$ .

5 0

3 years ago

Using the reaction below: 2 CO2(g) + 2 H2O(l) → C2H4(g) + 3 O2(g) ΔHrxn= +1411.1 kJ What would be the heat of reaction for this

maw [93]

Answer: d) -705.55 kJ

Explanation:

Heat of reaction is the change of enthalpy during a chemical reaction with all substances in their standard states.

$2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)$ $\Delta H=+1411.1kJ$

Reversing the reaction, changes the sign of $\Delta H$

$C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)$

$\Delta H=-1411.1kJ$

On multiplying the reaction by $\frac{1}{2}$ , enthalpy gets half:

$0.5C_2H_4(g)+1.5O_2(g)\rightarrow CO_2(g)+H_2O(l)$ $\Delta H=\frac{1}{2}\times -1411.1kJ=-705.55kJ/mol$

Thus the enthalpy change for the given reaction is -705.55kJ

7 0

3 years ago

When ammonium chloride is added to water and stirred, it dissolves spontaneously and the resulting solution feels cold. Without

d1i1m1o1n [39]

When ammonium chloride NH4Cl is added to water and stirred, it dissolves spontaneously (this is the basis for ΔG) for and the resulting solution feels cold (endothermic, the basis for ΔH). Without doing any calculations, we can easily deduce the signs of ΔG, ΔH, and ΔS for this process based on the observations.

ΔG < 0 (it is spontaneous)
ΔH < 0 (because the process is endothermic - it absorbs energy)
ΔS > 0 (entropy increases because of the dissolution of NH4Cl in water

7 0

3 years ago

What is the equation for the base ionization constant of PO4^3-

agasfer [191]

Chemical reaction of PO₄³⁻ ion in water:
PO₄³⁻(aq) + H₂O(l) → HPO₄²⁻(aq) +OH⁻(aq).
Kb = [HPO₄²⁻] · [OH⁻] / [PO₄³⁻]; <span>base ionization constant.
</span>Base ionization constant <span>is the equilibrium </span>constant<span> for the </span>ionization<span> of a </span>base<span>.
</span>According to Bronsted-Lowry theory acid are donor of protons and bases are acceptors of protons (the hydrogen cation or H⁺<span>).
</span>PO₄³⁻ is Bronsted base and it can accept proton and become conjugate acid HPO₄²⁻.

3 0

4 years ago

The lewis representation above depicts a reaction between a halogen (blue) and a main-group element from group (red). in this re

valina [46]

<h2><u>Full Question: </u></h2>

Attached in attachment.

<h2><u>Answer</u>:</h2>

Y is from Group 17. It needs 1 electron to complete its octet. There are total 6 lone pairs in molecule and 1 bond pair. The bond is covalent bond.

<h3><u>Explanation</u>:</h3>

In the picture given, we can see that it contains Lewis Dot structure of two elements X and Y. The X is said as a halogen and also correspondingly has 7 electrons in its outermost shell. The Y isn't mentioned which element it is, but similarly to X it also has 7 electrons in its outermost shell. So it is also a halogen. The group of the halogen is group 17. So Y belongs to group 17.

As the element has 7 electrons in its outermost shell, so it needs 1 electron to fulfill it's octet. It forms a covalent bond with X from where it gets 1 electron via sharing.

So now, there are three unshared electron pair of X and 3 unshared electron pair of Y. So a total of 6 unshared electron pair and 1 bond pair of electron between X and Y.

4 0

4 years ago