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Maslowich
3 years ago
9

Wich value gives the number of particles in 1 mol of a substance

Chemistry
2 answers:
juin [17]3 years ago
5 0

Answer: 6.022x10²³ (Avogadro's Number)

Explanation: The number of particles in 1 mole of a substance is determined by the Avogadro's Number.

exis [7]3 years ago
4 0
6.02x10 the power of 23 ( Avogadro formula)
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Sofia is trying to find the density of a 25.0 g irregularly shaped solid. She filled a graduated cylinder with 25.0 mL of water.
castortr0y [4]
The volume of the solid is
56.5 ml - 25 ml = 31.5 ml
The mass of the solid = 25g
So the density is Mass/ Volume
25/ 31.5 = 0.79 g/ml

Since the solid has a lower density (0.79 g/ml) than the density of water (1g/ml) it will float on water
4 0
2 years ago
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Write the correct name of the following compounds: <br> A. Sr(NO3)2 <br> B. CuBr2 <br> C. N2O4
nikdorinn [45]
A. Strontium nitrate;
B. Copper (II) bromide; 
C. Dinitrogen tetroxide.
5 0
2 years ago
Una piedra es lanzada horizontalmente desde la azote de un edificio de 30 metros de altura, con una velocidad de 12 m/s. Hallar
drek231 [11]

Answer: La piedra tarda 2.47 segundos en caer al suelo, y cae a 29.64 metros de la base del edificio.

Explanation:

Ok, tenemos 2 sistemas de ecuaciones para este problema.

Primero, el vertical:

La aceleración es la aceleración gravitatoria, entonces:

a = -9.8m/s^2

para la velocidad podemos integrar sobre el tiempo y obtenemos

v = (-9.8m/s^2)*t + v0

donde v0 es la velocidad inicial, pero la velocidad inicial es solo horizontal, entonces v0 = 0.

Para la posición integramos de vuelta:

p = (1/2)*(-9.8m/s^2)*t^2 + p0

donde p0 es la posición inicial, en este caso, 30m

p = (-4.9m/s^2)*t^2 + 30m

la piedra va a llegar al piso cuando la posición vertical sea igual a 0m

p = 0m =  (-4.9m/s^2)*t^2 + 30m

de aca podemos despejar el tiempo que la piedra tarda en llegar al suelo.

t = √(30/4.9) segundos = 2.47 s.

Ahora, las ecuaciones para el movimiento horizontal son:

Aceleración nula, pues no hay ninguna fuerza actuando en la dirección horizontal.

a = 0

para la velocidad, integramos sobre el tiempo:

v = 0*t + v0 = v0

donde v0 es la velocidad inicial, en este caso, es 12m/s

v = 12m/s

para la posición integramos de vuelta:

p = 12m/s*t + p0

en este caso podemos asumir que estamos inicialmente en el punto x = x0, asi que la posición inicial es p0 = x0.

p = 12m/s*t + x0

entonces, si queremos calcular la distancia entre la base del edificio y el punto donde cae la piedra, tenemos que calcular:

D = p(2.47s) - p(0s)

D = 12m/s*2.47s + x0 - (12m/s*0s + x0)

D = 29.64m

La piedra tarda 2.47 segundos en caer al suelo, y cae a 29.64 metros de la base del edificio.

3 0
3 years ago
How many atoms of hydrogen are in 4Ca(OH)2​
inn [45]

Explanation:

there are 8 atoms of hydrogen

5 0
2 years ago
A fuel was burned for 5 min, increasing the temperature of 10.0 g of water with a density of 1.00 g/ml by 9.0 oC. The fuel relea
jekas [21]

The fuel released 90 calories of heat.

Let suppose that water experiments an entirely <em>sensible</em> heating. Hence, the heat released by the fuel is equal to the heat <em>absorbed</em> by the water because of principle of energy conservation. The heat <em>released</em> by the fuel is expressed by the following formula:

Q = m\cdot c \cdot \Delta T (1)

Where:

  • m - Mass of the sample, in grams.
  • c - Specific heat of water, in calories per gram-degree Celsius.
  • \Delta T - Temperature change, in degrees Celsius.

If we know that m = 10\,g, c = 1\,\frac{cal}{g\cdot ^{\circ}C} and \Delta T = 9\,^{\circ}C, then the heat released by the fuel is:

Q = (10\,g)\cdot \left(1\,\frac{cal}{g\cdot ^{\circ}C} \right)\cdot (9\,^{\circ}C)

The fuel released 90 calories of heat.

We kindly invite to check this question on sensible heat: brainly.com/question/11325154

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2 years ago
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