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bixtya [17]
3 years ago
5

Oxidation is now defined in terms of change of oxidation number. Explore how earlier definitions of oxidation and reduction may

have led to conflicting answers for the conversion of P4 to H2PO2− and the way in which the use of oxidation numbers has resolved this.
Chemistry
1 answer:
Sav [38]3 years ago
5 0

Answer:

4

Explanation:

oxidation number resolved 4

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What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?
AlladinOne [14]

The question is incomplete, here is the complete question:

The given chemical reaction is:

2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3

What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?

<u>Answer:</u> The theoretical yield of copper is 44.48 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of aluminium = 12.6 g

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium}=\frac{12.6g}{27g/mol}=0.467mol

The given chemical equation follows:

2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of copper

So, 0.467 moles of aluminium will produce = \frac{3}{2}\times 0.467=0.7005mol of copper

Now, calculating the mass of copper  from equation 1, we get:

Molar mass of copper = 63.5 g/mol

Moles of copper = 0.7005 moles

Putting values in equation 1, we get:

0.7005mol=\frac{\text{Mass of copper}}{63.5g/mol}\\\\\text{Mass of copper}=(0.7005mol\times 63.5g/mol)=44.48g

Hence, the theoretical yield of copper is 44.48 grams

4 0
4 years ago
The mineral enargite is 48.41% cu, 19.02% as, and 32.57% s by mass. what is the empirical formula of enargite?
LuckyWell [14K]
Empirical formula is the simplest ratio of whole numbers of components in a compound. 
Assuming for 100 g of the compound 
                                Cu                                 As                             S
mass                      48.41 g                          19.02 g                      32.57 g
number of moles    48.41 / 63.5 g/mol      19.02 / 75 g/mol        32.57 / 32 g/mol 
                                = 0.762 mol                = 0.2536 mol            = 1.018 mol 
divide by the least number of moles 
                               0.762 / 0.2536             0.2536 / 0.2536         1.018 / 0.2536
                               = 3.00                          = 1.00                         = 4.01
once they are rounded off 
Cu - 3
As - 1
S - 4
therefore empirical formula is Cu₃AsS₄
8 0
3 years ago
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Rzqust [24]

Answer:

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Explanation:

i just know number 1 am nt sure of number 2

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nignag [31]

Answer:

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3 years ago
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What does the mass of an object measure?
anyanavicka [17]

Answer:

the amount of matter it contain

5 0
3 years ago
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