Answer:
Explanation:
It involves the thinking of it as an electrical interaction between the positively charged part of an atom and the negatively charged part as well. Succinctly put, the interaction between the proton of an atom and the electron of an atom.
The relationship between these two sub atomic particles is one of the basis for many chemical bonding, and this is inclusive of all the bonds there exist. Hydrogen, Electrovalent and even Covalent bondings to mention but a few
Answer:3Li+YbCl3=Yb +3LiCl
Explanation:as there are three cl in the first one so to balance them we will put 3before LiCl in order to make Cl balanced now there are 3 Li also so put before Li 3 making it also balanced Yb is balanced already
Answer:
Explanation:
Hello,
In this case, for a concentration of 0.42 M of benzoic acid whose Ka is 6.3x10⁻⁵ in 0.33 M sodium benzoate, we use the Henderson-Hasselbach equation to compute the required pH:
![pH=pKa+log(\frac{[base]}{[acid]} )](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D%20%29)
Whereas the concentration of the base is 0.33 M and the concentration of the acid is 0.42 M, thereby, we obtain:
![pH=-log(Ka)+log(\frac{[base]}{[acid]} )\\\\pH=-log(6.3x10^{-5})+log(\frac{0.33M}{0.42M} )\\\\pH=4.1](https://tex.z-dn.net/?f=pH%3D-log%28Ka%29%2Blog%28%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D%20%29%5C%5C%5C%5CpH%3D-log%286.3x10%5E%7B-5%7D%29%2Blog%28%5Cfrac%7B0.33M%7D%7B0.42M%7D%20%29%5C%5C%5C%5CpH%3D4.1)
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