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RideAnS [48]
2 years ago
9

Find the value of this expression if x = 7 and y= -2 xy^2/9

Mathematics
2 answers:
jeka942 years ago
5 0

7(−2)^2 /9

7(−2)^2 /9  

= 28 /9

tresset_1 [31]2 years ago
4 0

the answer above this is wrong if you’re using Plato

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Hellooopppppppppppppppp
schepotkina [342]

Answer:

150.88

Step-by-step explanation:

just gotta fine the area for each square using the formula base times height with a good old calculator and add them all together, hopefully that's correct

7 0
3 years ago
Which expression is a perfect cube ? <br><br> X^6<br> Y^24<br> M^28<br> S^64
guapka [62]

Answer: S^64

Step-by-step explanation:

S^4 - 4.4.4 = 64

5 0
3 years ago
Read 2 more answers
Mags has 2 1/4 pints of milk in her refrigerator. She lukes to have 1/4 with her oatmeal in the morning.How many bowls of oatmea
Yuliya22 [10]
9; in the two pints there are eight 1/4 pints, and the extra 1/4 makes nine 1/4 pints.
6 0
3 years ago
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Write a polynomial function with zeros -3,5,8​
klemol [59]

Answer:

x^3-10x^2+x+120

Step-by-step explanation:

Assuming you mean roots -3, 5, 8

These happen when we have (x+3)(x-5)(x-8)=0

Expand this

(x^2-2x-15)(x-8)=0

=x^3-2x^2-15x-8x^2+16x+120

=x^3-10x^2+x+120

3 0
2 years ago
Integrate Sec (4x - 1) Tan (4x - 1) Dx ​
Delicious77 [7]

\bf \displaystyle\int~sec(4x-1)tan(4x-1)dx \\\\[-0.35em] ~\dotfill\\\\ sec(4x-1)tan(4x-1)\implies \cfrac{1}{cos(4x-1)}\cdot \cfrac{sin(4x-1)}{cos(4x-1)}\implies \cfrac{sin(4x-1)}{cos^2(4x-1)} \\\\[-0.35em] ~\dotfill\\\\ \displaystyle\int~\cfrac{sin(4x-1)}{cos^2(4x-1)}dx \\\\[-0.35em] ~\dotfill\\\\ u=cos(4x-1)\implies \cfrac{du}{dx}=-sin(4x-1)\cdot 4\implies \cfrac{du}{-4sin(4x-1)}=dx \\\\[-0.35em] ~\dotfill

\bf \displaystyle\int~\cfrac{~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{u^2}\cdot \cfrac{du}{-4~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies -\cfrac{1}{4}\int\cfrac{1}{u^2}du\implies -\cfrac{1}{4}\int u^{-2}du \\\\\\ -\cfrac{1}{4}\cdot \cfrac{u^{-2+1}}{-1}\implies \cfrac{1}{4}\cdot u^{-1}\implies \cfrac{1}{4u}\implies \cfrac{1}{4cos(4x+1)}+C

5 0
3 years ago
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