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2 years ago

PLZ ANSWER FIRST GETS BRAINLIEST + 20 POINTS

Mathematics

2 answers:

Ivanshal [37]2 years ago

5 0

Answer:

x=-2 y=5

Step-by-step explanation:

sleet_krkn [62]2 years ago

4 0

Answer:

x= -2, y = 5

Step-by-step explanation:

y = -4x-3

y = -2x+1

Set the two equations equal to each other

-4x-3 = -2x+1

Add 4x to each side

-4x-3 +4x = -2x+1+4x

-3 = 2x+1

Subtract 1 from each side

-3-1 = 2x+1-1

-4 =2x

Divide by 2

-4/2 = 2x/2

-2 =x

Now find y

y = -4x-3

y = -4(-2) -3

y = 8 -3

y =5

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15. Find the force on an electron crossing a uniform magnetic field of intensity 0.5 T WILII

EleoNora [17]

Answer:

F = 8.48 x $10^{-18}$ N

Step-by-step explanation:

The force on an electron in a magnetic field can be determined by;

F = qvB Sin θ

where: e is the electron, v is its velocity, B is the measure of the magnetic field, and θ is the angle of its path.

Thus,

q = -1.6 x $10^{-19}$ C

v = 106 m/s

B = 0.5 T

θ = $90^{o}$

So that,

F = 1.6 x $10^{-19}$ x 106 x 0.5

= 8.48 x $10^{-18}$ N

The force on the electron crossing the uniform magnetic field is 8.48 x $10^{-18}$ N.

8 0

3 years ago

Can you help?

Ber [7]

-5 1/3, -2 1/2, 3.75, 4.2 ( this is the order from least to greatest)

5 0

3 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

2 years ago

Find the radius of a circle which has a sector area of 9 pi whose central angle is 90 degrees.

Greeley [361]

Answer:360/90 = 4

Total area = 4 times that of the sector.

Step-by-step explanation:

A 90 deg sector has 1/4 the area of the circle.

Total circle area = 4*9pi = 36pi

3 0

2 years ago

Read 2 more answers

Find the area please and will make brainliest

puteri [66]

To find the area of the trapezoid, we only need the quantities a1 (long base), a2(short base) and h(height).

Area=(1/2)(a1+a2)*h
=(1/2)(9.9+4.7)(5.6)
=40.88 mm ²

Not sure what's expected to give for "type". Perhaps trapezoid or trapezium.

4 0

3 years ago