Answer:
Step-by-step explanation:
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76 degrees and 47 degrees?
Answer:
6.4 meters per second
Step-by-step explanation:
Sarah the cheetah ran 100 meters at a speed of 16.8 meters per second. An olympian ran the 100-meter dash in 9.6 seconds. How much faster was Sarah the cheetah’s speed, to the nearest tenth of a meter per second?
0.9 meters per second
1.6 meters per second
6.4 meters per second
10.4 meters per second
Speed = distance / time
Olympian's speed = 100 / 9.6 = 10.4 meters per second
Sarah's speed = 16.8 meters per second.
Difference in speed = 16.8 - 10.4 = 6.4
the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero
Answer:
x ∈ (-∞, 3) U (6, ∞).
Step-by-step explanation:
We use factorization and optain
Then, we have two critical points: x=3 and x=6. Now:
(i) for x < 3 we have that x-6 <0 and x-3 <0. Then (x-6)(x-3) > 0.
(ii) for 3 < x < 6 we have that x -6 <0 and x -3 > 0. Then (x-6)(x-3) < 0.
(iii) for x > 6 we have that x-6 >0 and x-3 > 0. Then, (x-6)(x-3) > 0.
conditions (i) and (iii) satisfy the inequatliy, then the solution is x ∈ (-∞, 3) U (6, ∞).
The graph is in the picture below.
Only two real numbers satisfy x² = 23, so A is the set {-√23, √23}. B is the set of all non-negative real numbers. Then you can write the intersection in various ways, like
(i) A ∩ B = {√23} = {x ∈ R | x = √23} = {x ∈ R | x² = 23 and x > 0}
√23 is positive and so is already contained in B, so the union with A adds -√23 to the set B. Then
(ii) A U B = {-√23} U B = {x ∈ R | (x² = 23 and x < 0) or x ≥ 0}
A - B is the complement of B in A; that is, all elements of A not belonging to B. This means we remove √23 from A, so that
(iii) A - B = {-√23} = {x ∈ R | x² = 23 and x < 0}
I'm not entirely sure what you mean by "for µ = R" - possibly µ is used to mean "universal set"? If so, then
(iv.a) Aᶜ = {x ∈ R | x² ≠ 23} and Bᶜ = {x ∈ R | x < 0}.
N is a subset of B, so
(iv.b) N - B = N = {1, 2, 3, ...}
