The minutes it takes him to run 10.5 miles is 180 minutes
<h3>How many minutes did it take him to run 10.5 miles?</h3>
The given parameters are
Speed = 3.5 miles per hour
Distance = 10.5 miles
The time is calculated as:
Time = Distance/Speed
So, we have
Time = 10.5 miles/3.5 miles per hour
Evaluate the quotient
Time = 3 hours
Convert to minutes
Time = 180 minutes
Hence, the minutes it takes him to run 10.5 miles is 180 minutes
Read more about speed at:
brainly.com/question/6504879
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Question 1. It is graph 3 since the y-intercept in the equation is -2 and the y-intercept on the graph 3 is -2. It is also a quadratic function.
Question 2. It is graph two because the equation listed represents a quadratic function that is positive (graph opens up).
Question 3. It is graph 4 since the y-intercept is 2 and the only graph with that intercept is graph 4. Also, the equation represents a linear function.
Hope this helped :))
<h2>Problem:</h2>
Choose all the expressions that are equal to 5/9×8.
A. 9÷5×8
B. 8/9×5
C. 5÷8×9
D. 5×1/9×8
E. 5×8
<h2>Solution:</h2>
<h2>Answer:</h2>
<u>B</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>D</u>
<h2>=============================</h2>
Hope it helps
<h2>=============================</h2>
Exponentail thingies
easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0
now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero
5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1
5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4
x=log₅1 and/or log₅4
second quesiton
same thing
1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero
2^x-8=9
2^x=8
x=3
2^x-2=0
2^x=2
x=1
x=3 or 1
first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3
Answer:
The amount of Polonium-210 left in his body after 72 days is 6.937 μg.
Step-by-step explanation:
The decay rate of Polonium-210 is the following:
(1)
Where:
N(t) is the quantity of Po-210 at time t =?
N₀ is the initial quantity of Po-210 = 10 μg
λ is the decay constant
t is the time = 72 d
The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.
First, we need to find the decay constant:
(2)
Where t(1/2) is the half-life of Po-210 = 138.376 days
By entering equation (2) into (1) we have:
Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.
I hope it helps you!
