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Ann [662]
3 years ago
15

HELLLLPPPP!!!! PLEASSSSEEEE! 50 POINTS!

Mathematics
2 answers:
DIA [1.3K]3 years ago
6 0

Answer:

Rectangle

Step-by-step explanation:

Vera_Pavlovna [14]3 years ago
3 0

Step-by-step explanation:

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>here's</em><em> your</em><em> solution</em>

<em> </em><em>=</em><em>></em><em> </em><em>in </em><em>first </em><em>figure</em><em> </em><em>,</em><em> </em><em>base </em><em>=</em><em> </em><em>5</em><em>.</em><em>5</em><em>,</em><em> </em><em>perpendicular</em><em> </em><em>=</em><em>7</em><em>.</em><em>8</em>

<em>=</em><em>></em><em> </em><em>h^</em><em>2</em><em> </em><em>=</em><em> </em><em>5</em><em>.</em><em>5</em><em>^</em><em>2</em><em> </em><em>+</em><em> </em><em>7</em><em>.</em><em>8</em><em>^</em><em>2</em>

<em>=</em><em>></em><em> </em><em>h^</em><em>2</em><em> </em><em>=</em><em> </em><em>3</em><em>0</em><em>.</em><em>2</em><em>5</em><em> </em><em>+</em><em> </em><em>6</em><em>0</em><em>.</em><em>8</em><em>4</em><em> </em>

<em>=</em><em>></em><em>h^</em><em>2</em><em> </em><em>=</em><em> </em><em>9</em><em>1</em><em>.</em><em>0</em><em>9</em>

<em>=</em><em>></em><em> </em><em>h </em><em>=</em><em> </em><em>√</em><em>9</em><em>1</em><em>.</em><em>0</em><em>9</em>

<em>=</em><em>></em><em> </em><em>h </em><em>=</em><em> </em><em>9</em><em>.</em><em>5</em>

<em> </em><em> </em><em>Both </em><em>figure</em><em> </em><em>are </em><em>congruent</em>

<em>enc </em><em>we </em><em>will </em><em>get </em><em>a </em><em>rectangle</em><em> </em><em>by </em><em>add </em><em>both </em>

<em>hope</em><em> it</em><em> helps</em>

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<h3>What is the volume of a right circular cylinder?</h3>

Suppose that the radius of the considered right circular cylinder be 'r' units.

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V = \pi r^2 h \: \rm unit^3

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A 6-inch-diameter ball is placed within the cylinder, and then the cylinder is filled with water.

We have to find the volume of the empty cylinder and then the volume of the ball.

Subtract the latter from the former.

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Subtracting

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