Answer:
6) F
7) B
Step-by-step explanation:
6)
60= 2[½(n -6) +2n +5]
Expand:
60= 2(½)(n -6) +2(2n) +2(5)
60= n -6 +4n +10
Simplify:
60= 5n +4
Minus 4 on both sides:
5n= 60 -4
5n= 56
Divide both sides by 5:
n= 56 ÷5
n= 11.2
Thus, option F is correct.
7)
13q +2= 9(q +6)
Expand:
13q +2= 9q +54
Bring q terms to one side, constant to the other:
13q -9q= 54 -2
Simplify:
4q= 52
Divide both sides by 4:
q= 52 ÷4
q= 13
Thus, option B is correct.
Cool problem
x and y are the digits
x+y=11
yx=2(xy)+34
I'm not sure how to solve this using legit math so use trial and error
the 1 digit numbers that could be possible are
9,2
8,3
7,4
6,5
5,6
4,7
3,8
2,9
all of them add up to 11
the pairs obtained by swiching the number are
92 and 29
83 and 38
74 and 47
65 and 56
we find which ones are equal when we subtract 34 from the larger number and divide by 2
92-34=58
58/2=29
92 and 29 work
83-34=49
49/2=24.5 not equal to 38 not work
74-34=40
40/2=20 47 not equal to 20 so doesn't work
65-34=31
31/2=15.5 not equal to 56 so doesn't work
the origonal number is 29
Answer: 10
Step-by-step explanation: 2 and 1/2 divided by 1/4 equals 10 times he must run around the track
Answer:
The area of the sector is 316.78
Step-by-step explanation:
Given the radius of the circle is 11 inches
We know that the area of the circle is=π
Area of the circle= π = 121π
Now this is the area of the total circle which covers all the 360°.
Now we should find the area of the sector which covers 300°.
360°---->121π
300°----->x
By cross multiplication we get π
x=316.78