The question is not complete so I will answer it with an example and a few assumptions. Follow the steps to find the answer to your question.
Important to note:
Your question is a z-scores problem
Assume that for the population of unemployed individuals the population standard deviation is 4 weeks.
Thus, we need to find the z-value.
The z-value is the sample mean decreased by the population mean, divided by the standard deviation that we assumed. So, we have:
Using any standard negative z-scores table, we can find that:
Thus, we get:
Therefore, the probability that a simple random sample of 60 unemployed individuals will provide a sample mean within 1 week of the population mean is 0.9476
Answer:
0.9476