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prisoha [69]
3 years ago
8

Hey, Whats The answer please explain your answer marking brainliest:D................................Im tired:C

Mathematics
1 answer:
butalik [34]3 years ago
6 0

Answer:

b

Step-by-step explanation: you really want this part bro?

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Solve the blank: This equation for this graph is y=____x + _______​
Marysya12 [62]

Answer:

y=3x+2

Step-by-step explanation:

3 0
3 years ago
A number line going from negative 4 to positive 4. What is the distance between 0 and –2? Use the number line to answer the ques
Nana76 [90]

Answer:

I wish <em>i could help </em>

Step-by-step explanation:

4 0
3 years ago
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What is the equation of the line that passes through the point (5, -6) and has a<br> slope of – 3/5
Inessa [10]

Answer:

The answer is

<h2>y =  -  \frac{6}{5} x - 3 \\</h2>

Step-by-step explanation:

To find an equation of a line when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1) \\

where

m is the slope

( x1 , y1) is the point

From the question the point is (5, -6) and slope - 3/5

The equation of the line is

y + 6 =  -  \frac{3}{5} (x - 5) \\ y + 6 =  -  \frac{3}{5} x + 3 \\ y =  -  \frac{6}{5} x + 3 - 6

We have the final answer as

y =  -  \frac{6}{5} x - 3 \\

Hope this helps you

3 0
3 years ago
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Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
How many zeros are in the standard form of six hundred thousand, twenty? Explain
creativ13 [48]
Standard form is the literal standard form you write numbers in, so it would be 600,020. Hope this helps!
3 0
3 years ago
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