Answer:
a.
Step-by-step explanation:
-1230<-220
Answer:
Choice A:
Step-by-step explanation:
means we looking for first term 5 and the sequence is going up by 2.
In general,
means you have first term 
and the sequence has a common difference of d.
So it is between the first two choices.
The explicit form of an arithmetic sequence is:
An equivalent recursive form is 
So d again here is 2.
So choice a is correct.
Answer:
5 more of the sum would be + 5 to the final answer you are adding
Step-by-step explanation:
Answer:
x = 14
Step-by-step explanation:
Solve for x:
90 = -4 + 2 x + 3 (x + 8)
3 (x + 8) = 3 x + 24:
90 = 3 x + 24 + 2 x - 4
Grouping like terms, 3 x + 2 x - 4 + 24 = (2 x + 3 x) + (-4 + 24):
90 = (2 x + 3 x) + (-4 + 24)
2 x + 3 x = 5 x:
90 = 5 x + (-4 + 24)
24 - 4 = 20:
90 = 5 x + 20
90 = 5 x + 20 is equivalent to 5 x + 20 = 90:
5 x + 20 = 90
Subtract 20 from both sides:
5 x + (20 - 20) = 90 - 20
20 - 20 = 0:
5 x = 90 - 20
90 - 20 = 70:
5 x = 70
Divide both sides of 5 x = 70 by 5:
(5 x)/5 = 70/5
5/5 = 1:
x = 70/5
The gcd of 70 and 5 is 5, so 70/5 = (5×14)/(5×1) = 5/5×14 = 14:
Answer: x = 14
We are dealing here with a uniform distribution ranging from 0 to 30 minutes. We need to calculate the probability that the unreliable bus will arrive before the reliable one. This probability is the area under the uniform distribution "curve" from 0 to 10 minutes. This constitutes 1/3 of the entire unform distr. curve. So the probability that the unreliable bus will arrive before the reliable one is 1/3, or 0.33. The probability that it will arrive AFTER the reliable bus is 2/3, or 0.67.
