Notice that the 2 expressions have 2 common terms.
(r-s) is just (s-r) times (-1)
similarly
(t-s) is just (s-t) times (-1)
this means that :
(r-s) (t-s) + (s-r) (s-t)=-(s-r)[-(s-t)]+(s-r) (s-t)
the 2 minuses in the first multiplication cancel each other so we have:
-(s-r)[-(s-t)]+(s-r) (s-t)=(s-r) (s-t)+(s-r) (s-t)=2(s-r) (s-t)
Answer:
d)<span>2(s-r) (t-s) </span>
Answer:
I am pretty sure u got it right
Step-by-step explanation:
:)
Given:
A right angled triangle.
To find:
The value of x.
Solution:
We have,
Base = x
Hypotenuse = 
In a right angle triangle,
For the given triangle,
Multiply both sides by .
Therefore, the required value of x is 
.
