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3 years ago

Help with #9 linked above! Please help!

Mathematics

1 answer:

jasenka [17]3 years ago

6 0

y = A(Bx - C)ⁿ + D

A is a vertical stretch (or shrink if |A| < 1)

B is a vertical shrink (or stretch if |B| < 1)

C is a shift to the right (or left if C is negative) → notice that Bx - C is "-C" so to take the opposite

D is a shift up (or down if D is negative)

when C = -3, it is a shift to the left 3 units

when D = -7, it is a shift down 7 units

Answer: B

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Annabelle’s bicycle has a wheel radius of 13 inches. She places a sticker on the wheel so that its minimum height above the grou

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Answer:

The answer is D on edgen

Step-by-step explanation:

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3 years ago

Read 2 more answers

Associations In Data:Question 10

Karo-lina-s [1.5K]

Answer:

$\bar X = \frac{62+63+68+72+79+80+83+93+94+95}{10}= 78.9$

$|62-78.9| = 16.9$

$|63-78.9| = 15.9$

$|68-78.9| = 10.9$

$|72-78.9| = 6.9$

$|79-78.9| = 0.1$

$|80-78.9| = 1.1$

$|83-78.9| = 4.1$

$|93-78.9| = 14.1$

$|94-78.9| = 15.1$

$|95-78.9| = 16.1$

$MAD = \frac{\sum_{i=1}^n |X_i -\bar X|}{n}$

And replacing we got:

$MAD =\frac{16.9+15.9+10.9+6.9+0.1+1.1+4.1+14.1+15.1+16.1}{10}= 10.12$

And the best anwer is

10.12

Step-by-step explanation:

We have the following data given:

62 63 68 72 79 80 83 93 94 95

And we need to begin finding the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X = \frac{62+63+68+72+79+80+83+93+94+95}{10}= 78.9$

Now we can find the mean absolute deviation like this:

$|62-78.9| = 16.9$

$|63-78.9| = 15.9$

$|68-78.9| = 10.9$

$|72-78.9| = 6.9$

$|79-78.9| = 0.1$

$|80-78.9| = 1.1$

$|83-78.9| = 4.1$

$|93-78.9| = 14.1$

$|94-78.9| = 15.1$

$|95-78.9| = 16.1$

And finally we can find the mean abslute deviation with the following formula:

$MAD = \frac{\sum_{i=1}^n |X_i -\bar X|}{n}$

And replacing we got:

$MAD =\frac{16.9+15.9+10.9+6.9+0.1+1.1+4.1+14.1+15.1+16.1}{10}= 10.12$

And the best anwer is

10.12

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3 years ago

Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

$n_B=4$

$\overline{x}_A=\overline{x}_B$

To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

$(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$54=\sum (x_i-\overline{x}_A)^2$

Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

Now, after combining both sets, we get

$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

$\sigma^2=\dfrac{54+100}{6+4}$

$\sigma^2=\dfrac{154}{10}$

$\sigma^2=15.4$

Therefore, the variance of combined set is 15.4.

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3 years ago

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Answer:

domain: [0, ∞)
range: (-∞, ∞)
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Step-by-step explanation:

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The domain is the horizontal extent, so is the interval from 0 to infinity, including 0.

The range is the vertical extent, so extends from negative infinity to positive infinity (all real numbers).

The graph does not pass the vertical line test: a vertical line intersects it in more than one place, so the relation is NOT a function.

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3 years ago

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k0ka [10]

Answer:b

Step-by-step explanation:

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3 years ago