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WITCHER [35]
4 years ago
15

A researcher is using a particle accelerator in an expriment studying isotopes. How can the researcher change on isotope into a

different isotope of the same element?
Chemistry
1 answer:
stiv31 [10]4 years ago
4 0

Neutron capture reactions.

<h3>Explanation</h3>

Isotopes of the same element have the same number of protons in each nucleus. However, their nucleus differ in the number of neutrons. Adding one or more neutrons to a nucleus will converts it to a different isotope of the same element.

Neutrons can be produced with a particle accelerator. The researcher might aim fast moving alpha particles \phantom{}_2^{4}\text{He} from the accelerator at a beryllium Be target.

\phantom{}_4^{9} \text{Be} + \phantom{}_2^4\text{He} \to \phantom{}_{\phantom{1}6}^{12}\text{C} + \phantom{}_{0}^{1} \text{n}

Doing so will convert beryllium-9 to carbon-12 and release one neutron.

The neutron produced in this process moves very fast ("fast neutrons"). It might knock protons or alpha particles off the target nucleus. This is undesirable since the nucleus will have a change in its proton number. It will end up belonging to a different element.

The researcher should reduce the speed of those neutrons. Passing neutrons through moderators greatly reduces their speed. Moderators are materials that are rich in light nuclei. They remove the energy of neutrons as the two collide. Examples of moderators are heavy water (D₂O) and graphite (carbon). Slow neutrons are easier to capture than fast-moving ones. Combining those slow-moving neutrons to the source isotope will likely produce a different isotope of the same element.

<h3><em>Reference</em></h3>

Vitz, Ed. et. al, "19.5: Neutron Bombardment", ChemPRIME (Moore et al.), Libretexts Chemistry, 2017

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What is the compound MnCl2 called?
givi [52]

Answer is Manganese(ii) chloride

To answer this, you need to know the charges for both Mn and Cl

Mn is in the transition metal category and is unique with having 3 levels of charges

manganese - MN

Manganese(ii) - Mn^2+

Manganese(iii) - Mn^3+


Cl is a nonmetal with the standard charge of Cl^-1

Since you have two charges that don't cancel out, they get switched.

So Cl would receive a positive 2. Because it was a positive 2, we can assume that it starts with Manganese(ii). Then we add chloride to the end of it as it ends with Cl.

8 0
3 years ago
If 36.0 g of NaOH (MM = 40.00 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the
Kobotan [32]

Answer:

Molarity of NaOH = 1.8 M.

Explanation:

From the question given above, the following data were obtained:

Mass of NaOH = 36 g

Molar mass of NaOH = 40 g/mol

Volume = 500 mL

Molarity of NaOH =?

Next, we shall determine the number of mole in 36 g of NaOH. This can be obtained as follow:

Mass of NaOH = 36 g

Molar mass of NaOH = 40 g/mol

Mole of NaOH =?

Mole = mass / molar mass

Mole of NaOH = 36 / 40

Mole of NaOH = 0.9 mole

Next, we shall convert 500 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

500 mL = 500 mL × 1 L / 1000 mL

500 mL = 0.5 L

Finally, we shall determine the molarity of NaOH. This can be obtained as follow:

Mole of NaOH = 0.9 mole

Volume = 0.5 L

Molarity of NaOH =?

Molarity = mole / Volume

Molarity of NaOH = 0.9 / 0.5

Molarity of NaOH = 1.8 M

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How is the law of conservation of matter represented in a chemical reaction?
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Answer:

By balancing the chemical equation  

Explanation:

The Law of Conservation of Matter states that matter cannot be destroyed nor created.

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Atoms are made of matter, so you must have the same number of each type of atom in the reactants as in the products. You must balance the equation.

Consider the reaction

2H₂ + O₂ ⟶ 2H₂O

You must have 2s in front of H₂ and H₂O to balance the atoms.

They give you four atoms of H and two atoms of O on each side of the arrow.

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