You're given that there's 152 students. Each student has 18 pencils. All you have to do is multiply 152 students x 18 pencils/student, to get 2,736 pencils.
Answer:
548.80
Step-by-step explanation:
$506.98 * 8.25%=
Hey!
You're right! This equation can definitely be solved by performing two operations on both sides. Let me show you how it's done.
First, let's write out our equation.
<span><em>Original Equation :</em>
</span>x + 53 = 15
Now that that's done, we'll be performing two operations on both sides. The operation we'll want to do is subtracting both sides of the equation by 53. We do this to get x on its own.
<em>Original Equation :</em>
x + 53 = 15
<em>New Equation {Added Subtract 53 to Both Sides} :</em>
x + 53 - 53 = 15 - 53
Now we have to solve the equation. Let's do the left side first.
<em>Left Side of the Equation :</em>
x + 53 - 53
<em>Left Side of the Equation {Solved} :</em>
x
Now, we'll solve the right side of the equation.
<em>Right Side of the Equation :</em>
15 - 53
<em>Right Side of the Equation {Solved} :</em>
-38
Now we can put both solutions to both sides of the equation together.
<em>New Equation :</em>
x = -38
Since this cannot be simplified any farther, this is our final answer. And that's it!
<em>So, now we know that in the equation x + 53 = 15,</em> x = -38
Hope this helps!
- Lindsey Frazier ♥
Answer:
We conclude that the sum of two rational numbers is rational.
Hence, the fraction will be a rational number. i.e.
∵ b≠0, d≠0, so bd≠0
Step-by-step explanation:
Let a, b, c, and d are integers.
Let a/b and c/d are two rational numbers and b≠0, d≠0
Proving that the sum of two rational numbers is rational.

As the least common multiplier of b, d: bd
Adjusting fractions based on the LCM



As b≠0, d≠0, so bd≠0
Therefore, we conclude that the sum of two rational numbers is rational.
Hence, the fraction will be a rational number. i.e.
∵ b≠0, d≠0, so bd≠0