<span>61, 58, 57, 64, 59, 57, 64, 58, 56, 57.
put in order</span><span>
56, 57,57,57,58, 58, 59, 61, 64 , 64
answer is B. matching with data set</span>
Answer:
Given : The high school stadium contains a track that surrounds a soccer field. The soccer field is 100 yards long and 70 yards wide.
The school decided to cover the semicircles with grass to create a space for stretching and other activities.
To Find: area of one of the semicircles at either end of the track
How many square yards of grass will the school need to cover the entire circle?
Solution:
Diameter of semicircle = 70 yards
Radius of semicircle = 70/2 = 35 yards
Area of semicircle at one end = (1/2)πr²
= (1/2)(22/7)35²
= 1,925 sq yards
area of one of the semicircles at either end of the track = 1,925 sq yards
square yards of grass will the school need to cover the entire circle
= 2 x 1,925
= 3850 sq yards
distance around one of the semicircles at either end of the soccer field = πr = (22/7) 35 = 110 yards
distance around the inner lane of the track = 100 + 100 + 110 + 110
= 420 yards
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Hope this Helps
EXPLANATION:
-To formulate an equation, you must first know what data the exercise gives us to locate them correctly.
data:
-6 that must be added to a number.
-four times a number that is equal to 4x
-a result that is equal to 50
Now with these data we formulate the equation:
if we solve the equation we have:
the yearly increase of x% assumes is compounding yearly, so let's use that.
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