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eduard
3 years ago
10

Describe the end behavior of f(x)=3x^5+2x^3-1x+3

Mathematics
1 answer:
emmasim [6.3K]3 years ago
8 0

Answer:

Step-by-step explanation:

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A specifiic shade of green glaze requires 5 parts blue to 3 parts yellow. A glaze mixture contains 25 quarts of blue and 9 quart
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Remove 10 quarts from blue

5 parts blue 3 parts yellow
5 parts blue 3 parts yellow
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total: 15 parts blue
      9 parts yellow

remove the remaining 10 parts blue, since you do not have any more yellow 


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3 years ago
Tsits Cat
8090 [49]

Answer:

the trinagne

Step-by-step explanation:

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3 years ago
Express 3 as power of 3​
Alex17521 [72]

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3 years ago
Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)
Amanda [17]

Answer:

f_x(x,y,z)=4\sin (y-z)

f_x(x,y,z)=4x\cos (y-z)

f_z(x,y,z)=-4x\cos (y-z)

Step-by-step explanation:

The given function is

f(x,y,z)=4x\sin (y-z)

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

f_x(x,y,z)=4(1)\sin (y-z)

f_x(x,y,z)=4\sin (y-z)

Differentiate partially w.r.t. y and x, z are constants.

f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)

f_y(x,y,z)=4x\cos (y-z)

Differentiate partially w.r.t. z and x, y are constants.

f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)

f_z(x,y,z)=4x\cos (y-z)(-1)

f_z(x,y,z)=-4x\cos (y-z)

Therefore, the first partial derivatives of the function are f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z).

4 0
3 years ago
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