All categories

3 years ago

Find the taylor series for xex about x = 0. then integrate term-by-term and substitute to show that the series

1 answer:

katrin2010 [14]3 years ago

7 0

The Taylor series for e^x about x = 0 is

1 + x + x^2/2! + x^3/3! + x^4 /4!+...

xe^x = x + x^2 + x^3/2! + x^4/3! + x^5/4!+....

Integrating term by term gives:-

x^2/ 2 + x^3/3 + x^4 / 3.2! + x^5 / 4.3! + x^6 / 5.4!+....

You might be interested in

X^2 + y^2 - 6y + 4x = 36

zysi [14]

It is AAaaaaaaaaaaaaaaaaaa

6 0

2 years ago

Given g(x) = 10x + 2, find x when g(x) = 2.

Elan Coil [88]

Answer:

x=0

Step-by-step explanation:

We are given:

g(x) =10x +2

and

g(x)=2

g(x) is equal to both 10x+2 and 2. Therefore, by substitution, we can set them equal to each other

10x+2=2

Now, we need to solve for x. First, move all the numbers to the same side. Subtract 2 from both sides

10x+2-2=2-2

10x=0

To solve for x, we have to get x by itself. x and 10 are being multiplied. To get x alone, divide both sides by 10.

10x/10=0/10

x=0

8 0

2 years ago

Given f(x) = 10 -2xfind f(7). –4 3 7 56

strojnjashka [21]

Answer: $f(7)=-4$

Step-by-step explanation:

1. You have the following function given in the problem:

$f(x)=10-2x$

2. Then, to find $f(7)$ asked in the exercise, you only need to substitute $x=7$ (which is the input value) into the given function.

3. Therefore, keeping the above on mind, you obtain that $f(7)$ is:

$x=7$

$f(7)=10-2(7)$

$f(7)=10-14$

$f(7)=-4$

3 0

2 years ago

Read 2 more answers

Factorise x^2/4-y^2/4

Nuetrik [128]

Answer:

$\large\boxed{\left(\dfrac{x}{2}-\dfrac{y}{2}\right)\left(\dfrac{x}{2}+\dfrac{y}{2}\right)=\dfrac{x-y}{2}\cdot\dfrac{x+y}{2}}$

Step-by-step explanation:

$\dfrac{x^2}{4}-\dfrac{y^2}{4}=\dfrac{x^2}{2^2}-\dfrac{y^2}{2^2}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\=\left(\dfrac{x}{2}\right)^2-\left(\dfrac{y}{2}\right)^2\qquad\text{use}\ (a-b)(a+b)=a^2-b^2\\\\=\left(\dfrac{x}{2}-\dfrac{y}{2}\right)\left(\dfrac{x}{2}+\dfrac{y}{2}\right)=\dfrac{x-y}{2}\cdot\dfrac{x+y}{2}$

3 0

2 years ago

What is 699,900 rounded to the nearest thousand

Rus_ich [418]

<span>When you round 699,900 to the nearest hundred, you get 700,00.</span>

6 0

3 years ago

Read 2 more answers