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natima [27]
3 years ago
11

There are 16 dogs at the dog park last Saturday, and 6 of them were poodles. Considering this data, how many of the next 10 dogs

to arrive at the park next Saturday should you expect to be poodles?
Mathematics
2 answers:
aliina [53]3 years ago
8 0
I think it is 3

Hope this helps good luck
Radda [10]3 years ago
4 0

Answer:

There were 6 dogs at the dog park last Saturday, and 2 of them were German shepherds. Considering this data, how many of the next 12 dogs to arrive at the park next Saturday should you expect to be German shepherds?

German shepherds

Step-by-step explanation:

There were 6 dogs at the dog park last Saturday, and 2 of them were German shepherds. Considering this data, how many of the next 12 dogs to arrive at the park next Saturday should you expect to be German shepherds?

Germav

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A 2-column table with 4 rows. Column 1 is labeled Store with entries A, B, C, D. Column 2 is labeled Advertised Bread Prices wit
Alexxx [7]

Answer: I too need the answer to this for my little brother

Step-by-step explanation:

7 0
3 years ago
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The half-life of Radium-226 is 1590 years. If a sample contains 400 mg, how many mg will remain after 2000 years?
Assoli18 [71]

Answer:

167.27 mg.

Step-by-step explanation:

We have been given that the half-life of Radium-226 is 1590 years and a sample contains 400 mg.

We will use half life formula to solve our given problem.

N(t)=N_0*(\frac{1}{2})^{\frac{t}{t/2}, where N(t)= Final amount after t years, N_0= Original amount, t/2= half life in years.

Now let us substitute our given values in half-life formula.

N(2000)=400*(\frac{1}{2})^{\frac{2000}{1590}

N(2000)=400*(0.5)^{1.2578616352201258}    

N(2000)=400*0.4181633028874878239

N(2000)=167.26532115499512956\approx 167.27

Therefore, the remaining amount of Radium-226 after 2000 years will be 167.27 mg.

3 0
3 years ago
Increase £500 by 3.2% how do you work it out
yan [13]

£500·(1+3.2%)=£500 + £500·3.2%=£500 + £500·3.2/100 = £500 + £5·3.2 = £500 + £16=£516.

Green eyes.

8 0
3 years ago
you saved $10,943.89 in an emergency fund. One fourth is in a regular savings account at a 3.5% APR and the remainder is in a 30
Naddika [18.5K]
4.57%−3.5%
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8 0
3 years ago
Read 2 more answers
Simplifying Nonperfect Roots
Bond [772]
Short Answer:Choice C [Third one down]
Remark

Start with the number so I can talk about the basic principle at work. The way to work it is to factor 162 into prime factors and hope there are at least 3 that are the same. 
162 = 2 * 81
162 = 2 * 3 * 3 * 3 * 3

Now When you take the cube root of that, you get \sqrt[3]{2*2*2*2*3}
Here's the rule for a cube root. For every 3 prime factors under the cuberoot sign, you take out one and throw the other two away. So for cube root of 81,
you would factor it as ∛(81) = ∛(3 * 3 * 3 * 3) = 3∛3.

So out of four 3s under the cube root sign,  you have 1 outside the root sign and one inside the root sign. 2 of the four 3s have been thrown away.

Continuation.
X first
You want 2 xs outside the root sign
∛(x * x * x * x * x *x ) = (x * x)  You have thrown away 2 xs for every x outside the cube root sign
C = 6 There are no left overs.

Y second
For the ys, you need 1 outside and 2 inside the root sign. that's because you need 5 altogether.
∛(y * y * y * y * y) = y ∛y^2

Answer 
c = 6; d = 2
Choice C <<<<<< answer 
3 0
3 years ago
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