Nice twist of similar questions.
There are 7*6*5=210 possible 3-digit numbers formed by digits 1-7 without repetition.
For numbers greater than 700, the first digit must be 7.
Of the 30, the last digit must be a 2,4, or 6 to be an even number, that leaves 3 possibilities for the last digit.
The middle digit can be any number of the remaining 5 digits.
So the number of qualifying candidates would be
1*5*3=15 (1 for the first digit, 5 choices for the second, and 3 choices for the last digit).
Probability of randomly choosing a qualifying candidate (>700 & even) is therefore 15/210=1/14
Answer: y=4x + 7
Step-by-step explanation:
Add 7 to both sides that’s what I meant to say in the last bit of explanation in the attachment below
Given :
Two mean absolute value deviation 15.2 and 10.9 .
To Find :
Which mean absolute value deviation represents more consistency 15.2 or 10.9 .
Solution :
First we should know what is mean absolute deviation ( M.A.D) is :
M.A.D of a data set is the average distance between each data value and the mean .
It also describe the variation in a data set .
Also , high variability means the data is spread out and low variability means that data is clustered .
So, low variation means more consistency and vice-versa .
Therefore , 10.9 M.A.D is more consistent .
Hence , this is the required solution .
Step-by-step explanation:
Eliminate the x:
Eliminate the y:
<u>Answer:</u>
245 days per year ; 1715 hours per year
<u>Step-by-step explanation:</u>
Every emplyoee works 5 days per week , 49 weeks per year. So,
Every employee works,
days = 245 days per year .
Every employee works 7 hours per day,
so, every employee works 
hours
= 1715 hours per year .
