Answer:
A: y = 4x + 7
Step-by-step explanation:
Step 1: Our line is parallel to this line, so it has the same slope, but a different y-intercept, so set up the equation...
y = 4x + b
We are given a point (x, y) of (2, 15), so plug that in and solve for b.
15 = 4(2) + b
15 = 8 + b (simplify)
7 = b (subtract 8 from both sides to isolate b)
So the equation of our line is y = 4x + 7
Answer:
The answer is: 
Step-by-step explanation:
We are given: 
and 
We need to find 
.
Simply divide 
and 
.
Which equates to:
This cannot be simplified further, so it is the answer.
Remember that a quadratic equation is a parabola. The equation is of the type y = Ax^2 + Bx + C
A linear equation is a straight line. The equation is of the type y = MX + N
The soluction of that system is Ax^2 + Bx + C = MX + N
=> Ax^2 + (B-M)x + (C-N) = 0
That is a quadratic equation.
A quadratic equation may have 0, 1 or 2 real solutions. Those are all the possibilitis.
So you must select 0, 1 and 2.
You can also get to that conclusion if you draw a parabola and figure out now many point of it you can intersect with a straight line.
You will realize that depending of the straight line position it can intersect the parabola in none point, or one point or two points.
