Answer:
The total fish is 65
(PLEASE MARK BRAINLIEST)
Explanation:
65 x 0.80 = 52
Therefore, that shows that 80 percent is equal to 52 fish, and there are 13 remaining fish that are not freshwater.
You multiply top and bottom of the fraction by the conjugate of 5 - √2 which is 5 + √2. This produces a rational denominator:-
= √7 ( 5 + √2) / (5 - √2)(5 + √2)
= √7 ( 5 + √2) / (25 -2)
= (√7 ( 5 + √2)) / 23 answer
1=6/6
1/6 does not = 6/6
6/6=1, because 6 divide by 6=1
1/6 does not equal 1, because 1 divide by 6 = 1/6
The second garden plot will require 8√5 feet more fence than the first garden plot.
Further explanation:
In order to find the fence, we have to find the perimeter of both squares
So,
Area of Square 1: A1=180 square feet
Area of Square 2: A2=320 Square feet
Let x be the side of square 1:
Then,
![A_1=x^2\\180=x^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{180}=\sqrt{x^2}\\x=\sqrt{2*2*3*3*5}\\x=\sqrt{2^2*3^2*5}\\x=2*3\sqrt{5}\\x=6\sqrt{5}](https://tex.z-dn.net/?f=A_1%3Dx%5E2%5C%5C180%3Dx%5E2%5C%5CTaking%5C%20square%5C%20root%5C%20on%5C%20both%5C%20sides%5C%5C%5Csqrt%7B180%7D%3D%5Csqrt%7Bx%5E2%7D%5C%5Cx%3D%5Csqrt%7B2%2A2%2A3%2A3%2A5%7D%5C%5Cx%3D%5Csqrt%7B2%5E2%2A3%5E2%2A5%7D%5C%5Cx%3D2%2A3%5Csqrt%7B5%7D%5C%5Cx%3D6%5Csqrt%7B5%7D)
For second square:
Let y be the side of second square
![A_2=y^2\\320=y^2\\Taking\ square\ root\ on\ both\ sides\\\sqrt{320}=\sqrt{y^2}\\y=\sqrt{2*2*2*2*2*2*5}\\y=\sqrt{2^2*2^2*2^2*5}\\y=2*2*2\sqrt{5}\\y=8\sqrt{5}](https://tex.z-dn.net/?f=A_2%3Dy%5E2%5C%5C320%3Dy%5E2%5C%5CTaking%5C%20square%5C%20root%5C%20on%5C%20both%5C%20sides%5C%5C%5Csqrt%7B320%7D%3D%5Csqrt%7By%5E2%7D%5C%5Cy%3D%5Csqrt%7B2%2A2%2A2%2A2%2A2%2A2%2A5%7D%5C%5Cy%3D%5Csqrt%7B2%5E2%2A2%5E2%2A2%5E2%2A5%7D%5C%5Cy%3D2%2A2%2A2%5Csqrt%7B5%7D%5C%5Cy%3D8%5Csqrt%7B5%7D)
Perimeter of First Square:
![P_1=4x\\=4(6\sqrt{5})\\=24\sqrt{5}\ feet](https://tex.z-dn.net/?f=P_1%3D4x%5C%5C%3D4%286%5Csqrt%7B5%7D%29%5C%5C%3D24%5Csqrt%7B5%7D%5C%20feet)
Perimeter of Second Square:
![P_2=4y\\=4(8\sqrt{5})\\=32\sqrt{5}\ feet](https://tex.z-dn.net/?f=P_2%3D4y%5C%5C%3D4%288%5Csqrt%7B5%7D%29%5C%5C%3D32%5Csqrt%7B5%7D%5C%20feet)
The smaller perimeter will be subtracted from larger perimeter to find that how much more fence will be needed.
![P_2-P_1=32\sqrt{5}-24\sqrt{5}\\=(32-24)\sqrt{5}\\=8\sqrt{5}\ feet](https://tex.z-dn.net/?f=P_2-P_1%3D32%5Csqrt%7B5%7D-24%5Csqrt%7B5%7D%5C%5C%3D%2832-24%29%5Csqrt%7B5%7D%5C%5C%3D8%5Csqrt%7B5%7D%5C%20feet)
The second garden plot will require 8√5 feet more fence than the first garden plot.
Keywords: Radicals, Operations on Radicals
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