I believe this is how you do it...
AI=5, 5 squared=25
IF=12, 12 squared=144
144+25 (only because line A F is bigger than AI or IF does it add)
A F=169
2x = 8 ... therefore x = 4
4^2 = 16
Thousand
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The frequency distribution table shows the distribution of the rice consumed by the families
- The range is 40
- The class width is 7
- The interval with the highest frequency is 34 - 40
<h3>How to construct the frequency table?</h3>
From the question, we have the interval to be:
Interval = 6
Start by calculating the range
Range = Highest - Least
This gives
Range = 60 - 20
Range = 40
Calculate the class width
Width = Range/Interval
This gives
Width = 40/6
Width = 7
So, the classes are: 20 - 26, 27 - 33, 34 - 40, 41 - 47, 48 - 54 and 55 - 61
Using the above classes, we have the following frequency distribution table.
<u>Class Frequency</u>
20 - 26 6
27 - 33 3
34 - 40 7
41 - 47 4
48 - 54 3
55 - 61 4
From the above Frequency Distribution Table, the interval with the highest frequency is 34 - 40
Read more about Frequency Distribution Table at:
brainly.com/question/1094036
7√24 + √90 - 8√54
= 14√6 + 3√10 - 24√6
= 3√10 - 10√6
answer
D. last one
3√10 - 10√6
