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Ray Of Light [21]
3 years ago
6

Under his cell phone plan, Aaron pays a flat cost of $49 per month and $3 per

Mathematics
1 answer:
statuscvo [17]3 years ago
5 0

Answer:

The inequality would be $49 + g is less than $55

Step-by-step explanation:

I think that g would be 1 because that would make the bill $52 and it says that he wants to keep the bill under $55 not the same as $55

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How to find unknown side
Elan Coil [88]

Answer:

C = 10

Step-by-step explanation:

Find the last side of the triangle using the Pythagorean theorem.

a^{2} +b^{2} =c^{2}

You have a and b already, a = 6, b = 8

6^{2} +8^{2} =c^{2} \\\\

solve this to get

64 + 36 = \sqrt{100}

C = 10

Apply the same to the other 2 triangles. C is your longest side!

3 0
2 years ago
Find k. ..................​
Nonamiya [84]

Answer:

k = -10

Explanation:

f(x) = 4x³ - 3kx² + 44x - 30

The divisor is:

  • (x - 2)

Set divisor to zero:

  • (x - 2) = 0
  • x = 2

Insert this into equation.

⇒ 4(2)³ - 3k(2)² + 44(2) - 30 = 210

⇒ 32 - 12k + 88 - 30 = 210

⇒ -12k + 90 = 210

⇒ -12k = 210 - 90

⇒ -12k = 120

⇒ k = 120/-12

⇒ k = -10

6 0
2 years ago
Read 2 more answers
There are 24 pencils in a box. each student in a class gets 6 pencils. there are no pencils left over. how many students are in
Talja [164]
24/6=4 students

Pencils divided by how many each receive
5 0
3 years ago
A conical paper cup has a radius of 2 inches. Approximate, to the nearest degree, the angle β (see the figure) so that the cone
Aneli [31]
I don't know where the angle β is, so I will make the assumption that tanβ = h/r
V = \frac{1}{3} \pi r^{2} h

V volume = 60
r radius = 2
h = r tanβ

tan \beta = \frac{3V }{ \pi  r^{3} } = \frac{ 180}{25,1} = 7,17 \\  \\  \beta = 82
7 0
3 years ago
For what values of X are the statements below true
Galina-37 [17]

Answer:

See solutions below

Step-by-step explanation:

For what values of X are the statements below true

A. 1x>x+1

x >x+1

x-x>1

0x > 1

x > 1/0

X >∞

B) |1-x|>3

The fucntion can both be positive and negative

For the negative function

-(1-x) > 3

-1+x > 3

x > 3+1

x > 4

For the positive function

1-x > 3

-x > 3 - 1

-x > 2

x < -2

Hence the required solutions are x > 4 and x < -2

c) For the equation

|x-15| < 0

-(x - 15) < 0

-x + 15 < 0

-x < -15

x > 15

Also x-15 < 0

x < 0+15

x < 15

Hence the required solution is x > 15 and x < 15

3 0
3 years ago
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