Answer:
Step-by-step explanation:
Assuming this complete question:
"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean kilograms and standard deviation kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.
"
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where and
And the best way to solve this problem is using the normal standard distribution and the z score given by:
We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.
We can convert the corresponding z score for x=42.6 like this:
So then the corresponding z scale would be:
We first complete the square.
y=-x^2+2x+1
y=-x^2+2x-1+1+1
y=-(x-1)^2+2
The maximum point is (1,2) since -1 in ( ) meant 1 unit to the right and +2 meant 2 units up.
The maximum point is (1,2) but the maximum value means the y value which is simply just 2.
Done!
Answer:
cscA =
Step-by-step explanation:
Using the identity
csc x = , then
sinA = = = = , thus
cscA = =
Remember that an exponent means repeated multiplication.
The exponent of 4 means you have four 's mutiplied together:
And then each exponent of 2 inside means you have two 's multiplied inside each set of parentheses.:
There are 8 b's there when you expand this out.
34,650 is the answer, I think