OK, so the graph is a parabola, with points x=0,y=0; x=6,y=-9; and x=12,y=0
Because the roots of the equation are 0 and 12, we know the formula is therefore of the form
y = ax(x - 12), for some a
So put in x = 6
-9 = 6a(-6)
9 = 36a
a = 1/4
So the parabola has a curve y = x(x-12) / 4, which can also be written y = 0.25x² - 3x
The gradient of this is dy/dx = 0.5x - 3
The key property of a parabolic dish is that it focuses radio waves travelling parallel to the y axis to a single point. So we should arrive at the same focal point no matter what point we chose to look at. So we can pick any point we like - e.g. the point x = 4, y = -8
Gradient of the parabolic mirror at x = 4 is -1
So the gradient of the normal to the mirror at x = 4 is therefore 1.
Radio waves initially travelling vertically downwards are reflected about the normal - which has a gradient of 1, so they're reflected so that they are travelling horizontally. So they arrive parallel to the y axis, and leave parallel to the x axis.
So the focal point is at y = -8, i.e. 1 metre above the back of the dish.
Here’s the answer, hope it helps. Btw these are screenshots from someone else’s work not mine
Y-13=4(x-2)
y-13=4x-8
y=4x+5
Answer:
x=11
Step-by-step explanation:
M is the midpoint this means that we can set AM and BM equal to eachother, once this is done we can solve for x
9x-6=6x+27 (set equal to eachother)
9x=6x+33 (add 6)
3x=33 (subtract 6x)
x=11 (divide by 3)
The pattern is subtracting 9
