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3 years ago

What is the solution to a two-variable equation? pls answer

2 answers:

8 0

In general, a solution of a system in two variables is an ordered pair that makes BOTH equations true. In other words, it is where the two graphs intersect, what they have in common. So if an ordered pair is a solution to one equation, but not the other, then it is NOT a solution to the system

Sonbull [250]3 years ago

4 0

Answer:

A solution of a system of two linear equations is represented by an ordered pair (x,y). To determine if an ordered pair is a solution to a system of two equations, we substitute the values of the variables into each equation. If the ordered pair makes both equations true, it is a solution to the system

Step-by-step explanation:

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What is the length of LM ?

VLD [36.1K]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Simplify. (-2u?+u-3)+(4u²+7u+5)

Pavlova-9 [17]

Answer:

$2u^2+8u+2$

Step-by-step explanation:

$\left(-2u^2+u-3\right)+\left(4u^2+7u+5\right)$

$\blacksquare$ Remove parentheses:

$\longmapsto$ $-2u^2+u-3+4u^2+7u+5$

$\blacksquare$ Combine like terms:

$-2u^2+4u^2+u+7u-3+5$

$\longmapsto$ $-2u^2+4u^2=2u^2$

$\longmapsto$ $\:u+7u=8u$

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$\leadsto$ $2u^2+8u+2$

_______________________

3 0

3 years ago

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Which of the following can you determine, when you use deduction and start from a given set of rules and conditions? O A. What m

snow_tiger [21]

Answer:

Its C it must be true

Step-by-step explanation:

5 0

2 years ago

Can you please help me with this

olga_2 [115]

Answer:

y=-1/2x - 2

Step-by-step explanation:

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3 years ago

Simplify (-6^1/3)^(-2)=

Vlad1618 [11]

For this case we must simplify the following expression:

( $(-6 ^ {\frac {1} {3}}) ^ {- 2}$

So, by definition of power properties we have:

$a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}$

Then, rewriting the expression:

$\frac {1} {(- 6 ^ {\frac {1} {3}}) ^ 2} =\\\frac {1} {(- 6 ^ {\frac {1} {3}}) * (- 6 ^ {\frac {1} {3}})} =\\\frac {1} {(6 ^ {\frac {1} {3}}) * (6 ^ {\frac {1} {3}})} =\\\frac {1} {6 ^ {\frac {2} {3}}}$

ANswer:

$\frac {1} {6 ^ {\frac {2} {3}}}$

5 0

3 years ago