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4 years ago

What is the exact volume of the cylinder the height is 9 inches in the radius is 6 inches

Mathematics

1 answer:

Crazy boy [7]4 years ago

8 0

Answer:

324 $\pi$ inches cubed

Step-by-step explanation:

The volume of a cylinder is given by the formula: V = $\pi$ r^2 * h, where r is radius and h is the height.

Here, r = 6 and h = 9. So: V = $\pi$ * (6^2) * 9 = $\pi$ * 36 * 9 = 324 $\pi$

Thus, the answer is 324 $\pi$ inches cubed.

Hope this helps!

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posledela

each book cost 1.25

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10÷8= 1.25

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3 years ago

Andrew is working on his homework. One of the questions ask What is the next number is the pattern? 1,1,2,3,5,8.....? What kind

rusak2 [61]

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3 years ago

The shortest side of an isosceles triangle is 4x−2 inches long. The two longer sides are 5 inches longer than the shortest side.

crimeas [40]

Answer:

23 inches

Step-by-step explanation:

If we add 5 inches to the shortest side, all sides will be the same length and the perimeter will be 69 inches. The longest sides have length that is 1/3 that, or ...

... (1/3)·(64 +5 in) = 23 in

_____

You can solve for x, but you obviously don't need to.

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... (4x -2) + 2(4x -2 +5) = 64

... 12x +4 = 64

... 12x = 60

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6 0

3 years ago

The force pulling a truck downhill is 2,000N, the mass of the truck is 40,000 kg. What is the acceleration?

JulijaS [17]

For this case we have that Newton's second law is given by:

$F = m * a$

Where:

m: It's the mass

a: Acceleration

F: It's the force

According to the data we have:

$2,000 = 40,000 * a$

Dividing between 40,000 on both sides of the equation:

$a = \frac {2,000} {40,000}\\a = 0.05$

Thus, the acceleration is $0.05 \frac {m} {s ^ 2}$

Answer:

$0.05 \frac {m} {s ^ 2}$

7 0

4 years ago

(Step to step work)<br><br> sin x(cotx + tanx)

11Alexandr11 [23.1K]

solving $sin(x)(cot(x) + tan(x))$ we get $sec(x)$

Step-by-step explanation:

We need to solve: $sin(x)(cot(x) + tan(x))$

Solving:

We know:

$cot(x)=\frac{cos(x)}{sin(x)}\\ and\,\,tan(x)=\frac{sin(x)}{cos(x)}$

Putting the values of cot(x) and tan(x):

$sin(x)(cot(x) + tan(x))\\=sin(x)(\frac{cos(x)}{sin(x)}+\frac{sin(x)}{cos(x)})$

Taking LCM:

$=sin(x)(\frac{cos(x)cos(x)+sin(x)sin(x)}{sin(x)cos(x)})\\=sin(x)(\frac{cos^2(x)+sin^2(x)}{sin(x)cos(x)})$

We know that: cos^2x+sin^2x=1

and using identity: cos(x)sin(x)=sin(2x)*1/2

$=sin(x)(\frac{1}{sin(2x)\frac{1}{2}})\\=sin(x)(\frac{2}{sin(2x)})$

Using identity: sin(2x)=2cos(x)sin(x)

$=sin(x)(\frac{2}{2sin(x)cos(x)})\\Cancelling\,\,same\,\,terms\,\,in\,\,numerator\,\,and\,\,denominator:\\=\frac{1}{cos(x)} \\=sec(x)$

So, solving $sin(x)(cot(x) + tan(x))$ we get $sec(x)$

Keywords: Trigonometry

Learn more about Trigonometry at:

#learnwithBrainly

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3 years ago