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Morgarella [4.7K]
3 years ago
15

On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance

(number of keys) from that key, and r is 2(1/12). Given an initial key frequency, output that frequency and the next 4 higher key frequencies.
Output each floating-point value with two digits after the decimal point, which can be achieved as follows:

print('{:.2f} {:.2f} {:.2f} {:.2f} {:.2f}'.format(your_value1, your_value2, your_value3, your_value4, your_value5))

Ex: If the input is:

440
(which is the A key near the middle of a piano keyboard), the output is:

440.00 466.16 493.88 523.25 554.37
Computers and Technology
1 answer:
lesantik [10]3 years ago
8 0

Answer:

In C:

#include <stdio.h>

#include <math.h>

int main(){

   float f0,r,temp;

   r = pow(2.0,1.0/12);

   printf("f0: ");    scanf("%f", &f0);

   temp = f0;

   for(int i = 0; i<=4;i++){

       f0 = f0 * pow(r,i);

       printf("%.2lf ", f0);

       f0 = temp;    }

   return 0;

}

Explanation:

This declares f0, r and temp as float

   float f0,r,temp;

This initializes r to 2^(1/12)

   r = pow(2.0,1.0/12);

This prompts the user for f0

   printf("f0: ");    scanf("%f", &f0);

This saves f0 in temp

   temp = f0;

This iterates the number of keys from 0 to 4

   for(int i = 0; i<=4;i++){

This calculates each key

       f0 = f0 * pow(r,i);

This prints the key

       printf("%.2lf ", f0);

This gets the initial value of f0

       f0 = temp;    }

   return 0;

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Overloading in methods are popular in programming, and why overloading is important.
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Answer:

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The overloading is important because it has the ability to design the multiple method by using similar name. It also provide the high flexibility to the programmers to call the same method in the data. overloading basically provide the high clarity in the code.

Overloading is used to achieved the compile time polymorphism.  

Following are program of function overloading in c++ are:

Class abc // creating class

{

public:

int p;

void fun() // function fun with no parameter/

{

cout<<” hello “;

}

void fun(int a) // function fun with parameter

{

p=a;

cout<<p;

}

};

int main() // main function

{

abc ob; // creating object

ob.fun();// print hello;

ob.fun(6);// print 6

return 0;

}

Explanation:

In this program the function fun() have same name but different signature in the main method we create the object of class abc i.e ob. ob.fun() this statement called the function with no parameter and ob.fun(6) this statement will called the function with integer parameter.

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gladu [14]

Answer:

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Explanation:

3 0
3 years ago
Read 2 more answers
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