G=Z6×Z2G=Z6×Z2 will do (where ZnZn denotes the cyclic group of order nn). As a direct product of cyclic (so abelian) groups, GG is again abelian. Given any element (x,y)∈G(x,y)∈G, the order of (x,y)(x,y) will be the least common multiple of the orders of x,y.x,y.
The order of xx must divide 66 and the order of yy must divide 2,2, so the order of (x,y)(x,y) is at most lcm(6,2)=6.lcm(6,2)=6. But |G|=|Z6|⋅|Z2|=6⋅2=12.|G|=|Z6|⋅|Z2|=6⋅2=12. Since no element of GG has order 12,12, then GG is not cyclic.
ANSWER
STEP-BY-STEP EXPLANATION
Given information
To estimate the above expression, we need to find the factors of the denominators to get the LCM
Factors of 12 = 2 x 2 x 3
Factors of 8 = 2 x 2 x 2
From the above factors, the LCM is 2 x 2 x 2 x 3 = 24
Therefore, LCM is 24
Each of the input changes is 1 unit.
Each of the output changes is 3 units, so the function is linear with a slope of 3.
The output is -2 when the input is 0, so the function is
.. y = 3x -2
Answer:
is number 3
Step-by-step explanation:
see explanation on the attached
hope it helps
