Step-by-step explanation:
Hey there!
Here;
The equations are;


Multiplying equation (i) by 2.
16x + 14y = 78
<u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>1</u><u>4</u><u>y</u><u> </u><u> </u><u> </u><u>=</u><u> </u><u>-68</u>
20x = 10

x = 1/2.
Putting value of 'x' in equation (i).




Therefore the value of y is 5.
<u>Check</u><u>:</u>
<u>Put</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>and</u><u> </u><u>y</u><u> </u><u>in</u><u> </u><u>equation</u><u> </u><u>(</u><u>i</u><u>)</u><u>.</u>
8x + 7y = 39



(True).
<u>Therefore</u><u>, </u><u>the</u><u> </u><u>solution</u><u> </u><u>is</u><u> </u><u>;</u><u> </u><u>(</u><u>1</u><u>/</u><u>2</u><u>,</u><u>5</u><u>)</u><u>.</u>
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Negative and Positive numbers dictate direction on a graph. Negative numbers indicate the point is moving left, and positive numbers indicate the point is moving right.
Answer: 1050
Step-by-step explanation:
Number of combinations of selecting r things out of n = 
such that 
Given: A restaurant menu has 5 kinds of soups, 7kinds of main courses, 6 kinds of desserts, and 5 kinds of drinks.
If a customer randomly selects one item from each of these four categories, then by fundamental counting principle , the number of different outcomes are possible = 
hence, total number of outcomes = 1050
Answer:
![\textbf{$x \in (-\infty, 3] $}\\](https://tex.z-dn.net/?f=%5Ctextbf%7B%24x%20%5Cin%20%28-%5Cinfty%2C%203%5D%20%24%7D%5C%5C)
Step-by-step explanation:
![\textup{Given:}\\$ 4x + 6 $\textup{Subtracting $6$ from both the sides }\\$ 4x \leq 18 - 6 \hspace{5mm} (=12) $\\\textup{Dividing by $4$ on both the sides: \hspace{15mm} [Note that the sign of the inequality changes only when we divide it by a negative number]}\\$$ x \leq 3 $$\\\textup{$x$ can be any real number less than or equal to 3.}\\$ \iff x \in R^- \cup \{a : 0 \leq a \leq 3\} $](https://tex.z-dn.net/?f=%5Ctextup%7BGiven%3A%7D%5C%5C%24%204x%20%2B%206%20%24%5Ctextup%7BSubtracting%20%246%24%20from%20both%20the%20sides%20%7D%5C%5C%24%204x%20%5Cleq%2018%20-%206%20%5Chspace%7B5mm%7D%20%28%3D12%29%20%24%5C%5C%5Ctextup%7BDividing%20by%20%244%24%20on%20both%20the%20sides%3A%20%5Chspace%7B15mm%7D%20%5BNote%20that%20the%20sign%20of%20the%20inequality%20changes%20only%20when%20we%20divide%20it%20by%20a%20negative%20number%5D%7D%5C%5C%24%24%20x%20%5Cleq%203%20%24%24%5C%5C%5Ctextup%7B%24x%24%20can%20be%20any%20real%20number%20less%20than%20or%20equal%20to%203.%7D%5C%5C%24%20%5Ciff%20x%20%5Cin%20R%5E-%20%5Ccup%20%5C%7Ba%20%3A%200%20%5Cleq%20a%20%5Cleq%203%5C%7D%20%24)