3 years ago

Some please help me I’ll give out brainliest please dont answer if you don’t know

Mathematics

1 answer:

Zolol [24]3 years ago

5 0

Answer:

(3a+2)(2a−7)

Step-by-step explanation:

Factor by grouping

6a2−17a−14

=(3a+2)(2a−7)

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pls vote me brainlyest

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ValentinkaMS [17]

Expanding the left side of the equation, it is found that since both sides are equal, yes, it is an identity.

An equality represents an identity if both sides are equal.

In this problem:

$(a - b)^4 = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4$

Expanding the left side:

$(a - b)^2(a - b)^2 = a^4 - 4a^3b + 6a^2b^2 + 4ab^3 + b^4$

$(a^2 - 2ab + b^2)(a^2 - 2ab + b^2) = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4$

$a^4 - 4a^3b + + 6a^2b^2 - 4ab^3 + b^4 = a^4 - 4a^3b + 6a^2b^2 - 4ab^3 + b^4$

Since both sides are equal, yes, it is an identity.

A similar problem is given at brainly.com/question/24866308

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3 years ago

Can anybody please help how to do these!! NO LINKS

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Answer:

22.

$rcos \theta = rsin \theta$

23.

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Step-by-step explanation:

To change the equation to polar form replace x with $rcos\theta$

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