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andreyandreev [35.5K]
4 years ago
5

Den pushes a desk 400 cm across the floor. He exerts a force of 10 N for 8 s to move the desk.

Physics
2 answers:
stellarik [79]4 years ago
7 0

Answer: The correct option is Option b.

Explanation:

Power is defined as the rate of work done by an object.

Mathematically,

P=\frac{W}{t}    .....(1)

And work done is the product of force exerted on the object times the displacement covered by that object.

Mathematically,

W=F.s

Putting this value in above equation, we get:

P=\frac{F.s}{t}

where,

P = power = ?W

F = Force exerted = 10N

s = Displacement = 400cm = 4m   (Conversion factor: 1m = 100 cm)

t = Time taken = 8s

Putting values in above equation, we get

P=\frac{10\times 4}{8}\\\\P=5W

Hence, the correct option is Option b.

kati45 [8]4 years ago
5 0
We Know, P = W/t
P = F * s/t
Here, F = 10N
s = 400cm = 4m
t = 8 sec.

Substitute their values in to expression,
P = 10 * 4/8
P = 10 * 1/2
P = 5 Watt

So, your final answer is 5 W

Hope this helps!
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The force that binds atoms together to form molecules is
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Answer:

The electromagnetic force

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7 0
3 years ago
Assume a satellite shines an unpolarized light on a telescope. The intensity of the light as it reaches the telescope is 1.1*10-
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Answer:

4.125\times 10^{-11}\ W/m^2

Explanation:

I_0 = Intensity of unpolarized light = 1.1\times 10^{-10}\ W/m^2

\theta = Angle of the filter = 30^{\circ}

Intensity of light is given by

I=\dfrac{I_0}{2}cos^2\theta\\\Rightarrow I=\dfrac{1.1\times 10^{-10}}{2}cos^230\\\Rightarrow I=4.125\times 10^{-11}\ W/m^2

The intensity of light detected by the camera is 4.125\times 10^{-11}\ W/m^2

7 0
4 years ago
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Answer:

Power of the string wave will be equal to 5.464 watt

Explanation:

We have given mass per unit length is 0.050 kg/m

Tension in the string T = 60 N

Amplitude of the wave A = 5 cm = 0.05 m

Frequency f = 8 Hz

So angular frequency \omega =2\pi f=2\times 3.14\times 8=50.24rad/sec

Velocity of the string wave is equal to v=\sqrt{\frac{T}{\mu }}=\sqrt{\frac{60}{0.050}}=34.641m/sec

Power of wave propagation is equal to P=\frac{1}{2}\mu \omega ^2vA^2=\frac{1}{2}\times 0.050\times 50.24^2\times 34.641\times 0.05^2=5.464watt

So power of the wave will be equal to 5.464 watt

6 0
3 years ago
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