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3 years ago

An incident ray parallel to the axis and one through the focal point reflect and converge at the image.

Physics

2 answers:

Grace [21]3 years ago

3 0

Answer:

The answer is true.

Explanation:

A ray coming from the object hits the surface of a mirror and then passes through focus point after reflection. Since the image is formed by the actual meeting of the reflected rays therefore it is called as real image. the direction of arrow will be upward.

Same is true if the object is placed at center of curvature the coming ray along the parallel axis passes through the focus and bends downward. The point where the two reflecting rays will meet is the point of image. And the direction of image arrow will be downward. In this case image is formed between F and C.

melomori [17]3 years ago

3 0

Answer:

TRUE

Explanation:

In mirrors, all rays of light incidented on a plane surface (mirror) and parallel to the principal axis converges at the focus of the mirror after reflection.

When forming the image of an object placed in front of a mirror (for example curved mirrors), there are two steps:

1. , all rays of light incidented on a plane surface (mirror) and parallel to the principal axis converges at the focus of the mirror after reflection.

2. Light rays from the object passes through the centre of curvature undeflected and reflect back on the same line of incidence

The two reflected rays from formed will intersect at a point and this point is where the image will be formed.

Based on the conclusion above the statement in question is TRUE i.e

an incident ray parallel to the axis and one through the focal point reflect and converge at the image.

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Marina CMI [18]

Explanation:

The equation of motion of an object is given by :

$h(t)=-16t^2+112t+128$

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So,

$-16t^2+112t+128=0$

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On solving above equation using online calculator, t = 8 seconds. So, the object hit the ground after 8 seconds. Hence, this is the required solution.

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mr_godi [17]

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2 years ago

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Ne4ueva [31]

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3 years ago

What is the energy released in this B- nuclear reaction 2K-> 2Ca0,e? (The atomic mass of 42 K is 41.962403 u and that of 42Ca

Katyanochek1 [597]

<u>Answer:</u> The energy released in the given nuclear reaction is 3.526 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

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