All categories

4 years ago

An incident ray parallel to the axis and one through the focal point reflect and converge at the image.

Physics

2 answers:

Grace [21]4 years ago

3 0

Answer:

The answer is true.

Explanation:

A ray coming from the object hits the surface of a mirror and then passes through focus point after reflection. Since the image is formed by the actual meeting of the reflected rays therefore it is called as real image. the direction of arrow will be upward.

Same is true if the object is placed at center of curvature the coming ray along the parallel axis passes through the focus and bends downward. The point where the two reflecting rays will meet is the point of image. And the direction of image arrow will be downward. In this case image is formed between F and C.

melomori [17]4 years ago

3 0

Answer:

TRUE

Explanation:

In mirrors, all rays of light incidented on a plane surface (mirror) and parallel to the principal axis converges at the focus of the mirror after reflection.

When forming the image of an object placed in front of a mirror (for example curved mirrors), there are two steps:

1. , all rays of light incidented on a plane surface (mirror) and parallel to the principal axis converges at the focus of the mirror after reflection.

2. Light rays from the object passes through the centre of curvature undeflected and reflect back on the same line of incidence

The two reflected rays from formed will intersect at a point and this point is where the image will be formed.

Based on the conclusion above the statement in question is TRUE i.e

an incident ray parallel to the axis and one through the focal point reflect and converge at the image.

You might be interested in

A car is traveling 35 mph on a smooth surface. If a balanced force is applied to the car, what happens?

zepelin [54]

Answer:

Here is the answer.

Explanation:

Balanced forces- they are those forces that produce 0 resultant forces.

therefore, on applying a balanced force on the object, it wouldn't result in any change, as resultant force would be 0.

7 0

4 years ago

A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.

kodGreya [7K]

Answer:

The z-component of the force is $\= F_z = 0.00141 \ N$

Explanation:

From the question we are told that

The charge on the particle is $q = 7.76 *0^{-8} \ C$

The magnitude of the magnetic field is $B = 0.700\r i \ T$

The velocity of the particle toward the x-direction is $v_x = -1.68*10^{4}\r i \ m/s$

The velocity of the particle toward the y-direction is

$v_y = -2.61*10^{4}\ \r j \ m/s$

The velocity of the particle toward the z-direction is

$v_y = -5.85*10^{4}\ \r k \ m/s$

Generally the force on this particle is mathematically represented as

$\= F = q (\= v X \= B )$

So we have

$\= F = q ( v_x \r i + v_y \r j + v_z \r k ) \ \ X \ ( \= B i)$

$\= F = q (v_y B(-\r k) + v_z B\r j)$

substituting values

$\= F = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r z) + [(5.58*10^{4}) (0.700)]\r y)$

$\= F= 0.00303\ \r j +0.00141\ \r k$

So the z-component of the force is $\= F_z = 0.00141 \ N$

Note : The cross-multiplication template of unit vectors is shown on the first uploaded image ( From Wikibooks ).

7 0

4 years ago

A 1.50-m cylindrical rod of diameter 0.500 cm is connected to a power supply that maintains a constant potential difference of 1

nydimaria [60]

Answer:

a) 1.06*10^-5

b) 0.00105 °C^-1

Explanation:

Given that

Length of the cylinder, L = 1.5 m

Radius of the cylinder, r = 0.25 cm

Voltage across the rod, V = 15 V

I• at Temperature T• = 20° C is 18.5 A

I at Temperature T = 90° C is 17.2 A

See attachment for calculations

5 0

3 years ago

A small hot-air balloon is filled with 1.01×106 l of air (d = 1.20 g/l). as the air in the balloon is heated, it expands to 1.10

lara31 [8.8K]

<span>Volume of air in the balloon 1.01 x 10^6 L
Density of air is 1.20 g/l
Mass = Density X Volume

So mass of the air in the Balloon= ( 1.01 x 10^6) X 1.20 = 1.212 x 10^6 g
As the air is heated, the volume of air in the balloon expands to 1.10x 10^6 L Density= Mass/ voume So the Density of heated air = 1.212 x 10^6/ 1.10x 10^6 = 1.101 g/l The answer is 1.101 g/l.</span>

5 0

3 years ago

A 66-kg fellow stands on a digital scale in an elevator that accelerates upwards from rest to 4.5 m/s in 2.00 s. show answer Inc

Nina [5.8K]

Answer:

Explanation:

mass of the fellow ( m ) = 66kg

acceleration of fellow a

v = u + at

4.5 = 0 + a x 2

a = 4.5 /2

= 2.25 m / s²

Net force acting on fellow in upward direction by the surface of elevator

R - mg where R is reaction force of the surface of the elevator

Applying Newton's law of motion

R - mg = ma

R = m (g +a )

= 66 x ( 9.8 + 2 )

= 778.8 N

This will be the scale reading .

7 0

3 years ago