I actually don't know how to explain to you, because there's no pointe name.
I just can tell you is use the big square minus the triangle on the top and minus the triangle on the bot.
Answer: 
<u>Step-by-step explanation:</u>
0° < A < 180° so it is in Quadrant I or II
since tan A is negative, it is in Quadrant II ---> (-x, +y)
Next, find the hypotenuse given that x = -13 and y = 9
(-13)² + (9)² = r²
250 = r²
5√10 = r
If we join the Center with different corners of the polygon,we find 10 Isoceles triangle with equal side=9.14cm, Making an angle of 36° between the equal sides.
Area of 1 triangle= a*b*sinC/2
= 9.14*9.14*Sin36°/2
= 9.14*9.14*0.587/2
=24.51 cm^2
Area of 10 triangle= 24.51*10
= 245.1cm^2
Answer:
-1/2
Step-by-step explanation:
hope this helps!
