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postnew [5]
3 years ago
10

What would be the result after the following code is executed? int[] numbers = {40, 3, 5, 7, 8, 12, 10}; int value = numbers[0];

for (int i = 1; i < numbers.length; i++) { if (numbers[i] < value) value = numbers[i]; } The value variable will contain the highest value in the numbers array. The value variable will contain the sum of all the values in the numbers array. The value variable will contain the average of all the values in the numbers array. The value variable will contain the lowest value in the numbers array.
Computers and Technology
1 answer:
maw [93]3 years ago
7 0

Answer:

The value variable will contain the lowest value in the numbers array.

Explanation:

Given

The given code segment

Required

The result of the code when executed

The illustration of the code is to determine the smallest of the array.

This is shown below

First, the value variable is initialized to the first index element

int value = numbers[0];

This iterates through the elements of the array starting from the second

 for (int i = 1; i < numbers.length; i++) {

This checks if current element is less than value.

     if (numbers[i] < value)

If yes, value is set to numbers[i]; which is smaller than value

value = numbers[i];

<em>Hence, the end result will save the smallest in value</em>

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Answer:

<u>D. In DMA, interrupt is sent when the task is completed</u>

Explanation:

Note, the term Direct Memory Access simply refers to a computer feature that allows hardware subsystems to directly access the main system memory of a computer, without any the aid of the central processing unit (CPU).

It is a fact that while the transfer process is ongoing, an interrupt (interrupt signal) is not sent until when the task is completed.

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3 years ago
What are the first and the last physical memory addressesaccessible using
Misha Larkins [42]

Answer

For First physical memory address,we add 00000 in segment values.

For Last physical memory address,we add 0FFFF in segment values.

<u>NOTE</u>-For addition of hexadecimal numbers ,you first have to convert it into binary then add them,after this convert back it in hexadecimal.

a)1000

For First physical memory address, we add 00000 in segment value

We add 0 at the least significant bit while calculating.

          1000<u>0</u> +00000 = 1000<u>0</u> (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           1000<u>0</u> +0FFFF =1FFFF    (from note)

b)0FFF

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

     0FFF<u>0</u> +00000=0FFF0 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           0FFF<u>0</u> +0FFFF =1FFEF (from note)

c)0001

For First physical memory address,we add 00000 in segment value

We add 0 at the least significant bit while calculating.

     0001<u>0</u> +00000=00010 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           0001<u>0</u> +0FFFF =1000F (from note)

d) E000

For First physical memory address,we add 00000 in segment value

 We add 0 at the least significant bit while calculating.

    E000<u>0</u> +00000=E0000 (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           E000<u>0</u> +0FFFF =EFFFF (from note)

e) 1002

For First physical memory address,we add 00000 in segment value

 We add 0 at the least significant bit while calculating.

    1002<u>0</u> +00000=10020  (from note)

For Last physical memory address,We add 0 at the least significant bit while calculating.

   we add 0FFFF in segment value

           1002<u>0</u> +0FFFF =2001F (from note)

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Answer:

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Explanation:

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Explanation:

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Answer:

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Explanation:

Hope this helps C:

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