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oksano4ka [1.4K]
3 years ago
10

In this experiment, you were asked to calculate your percent yield of alum assuming that you started with pure aluminum. Actuall

y, the aluminum had a plastic coating on it. Will the percent yield calculated (assuming pure aluminum metal) be higher, lower, or the same as the true percent yield (considering the plastic coating)? Explain

Chemistry
1 answer:
neonofarm [45]3 years ago
3 0

Answer:

Percent yield of alum is 38.6%

Explanation:

Find attached calculations for detailed explanation.

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4. A 0.51 kg solution contains 87 mg of potassium iodide. Calculate the W/W concentration
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Taking into account the definition of percentage composition, the percent composition of potassium iodide in this sample is 0.017%.

<h3>Definition of percent composition </h3>

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

To calculate the percentage of composition, it is necessary to know the mass of the element in a known mass of the compound.

<h3>Percentage Composition in this case</h3>

In this case, you know that a 0.51 kg (or 510000 mg, being 1 kg= 1000000 mg) solution contains 87 mg of potassium iodide.

Dividing the mass amount of potassium iodide present in the compound by the mass of the sample and multiplying it by 100 to obtain a percentage value, the percentage composition of potassium iodide is obtained:

percentage composition of potassium iodide=\frac{87 mg}{510000 mg} x100

<u><em>percentage composition of potassium iodide= 0.017%</em></u>

Finally, the percent composition of potassium iodide in this sample is 0.017%.

Learn more about percent composition:

brainly.com/question/24201923

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brainly.com/question/17030163

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