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2 years ago

Copper chloride cannot be produced by reacting copper with hydrochloric acid, why?

1 answer:

tatiyna2 years ago

5 0

The equation that you’re looking at is Cu (copper) + HCl (hydrochloric acid) —> CuCl (copper chloride). This doesn’t work because copper chloride doesn’t contain hydrogen. The equation would only work if the reactants were chlorine and copper only.

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Determine the molality of an aqueous solution that is 16.5 percent urea by mass

yarga [219]

Take a hypothetical sample of exactly 100 grams of the solution.

(16g urea) / (60.06 g urea/mol) = 0.2664 mol urea

((100 g total) - (16g urea)) = 84.0 g H2O = 0.0840 kg H2O

(0.2664 mol) /0.0840 (kg) = 3.17143mol/kg = 3.18m urea

7 0

3 years ago

Carry out the following operations as if they were calculations of experimental results and express each answer in standard nota

Shalnov [3]

Answer:

1. $10.6\; \rm m$ (one decimal place.)

2. $0.79\; \rm g$ (two decimal places.)

3. $16.5\;\rm cm^2$ (three significant figures.)

Explanation:

The first and second expressions are additions and subtractions. When adding two numbers, the accuracy of the result is given by the number of decimal places in it. The result should have as many decimal places as the input with the least number of decimal places.

For example, in the first expression:

$5.6792\;\rm m$ has four decimal places.
$0.6\; \rm m$ has only one decimal place.
$4.33\; \rm m$ has two decimal places.

Therefore, the result should be rounded to one decimal place. Note that these units are compatible for addition, since they are all the same. The result should have the same unit (that is: $\rm m$ .)

Therefore:

$\rm 5.6792\; m + 0.6\; m + 4.33\; m \approx 10.6\; \rm m$ . (Rounded to one decimal place.)

Similarly:

$\rm 3.70\; \rm g$ has two decimal places.
$2.9133\; \rm g$ has four decimal places.

Therefore, the result should be rounded to two decimal places. Its unit should be $\rm g$ (same as the unit of the two inputs.)

$\rm 3.70\; g - 2.9133\; g \approx 0.79\; \rm g$ . (Rounded to two decimal places.)

When multiplying two numbers, the accuracy of the result should be based on the number of significant figures in it. The result should have as many significant figures as the input with the least number of significant figures. In this expression:

$4.51\; \rm cm$ has three significant figures.
$3.6666\; \rm cm$ has five significant figures.

Therefore, the result should have only three significant figures.

The unit of the result is supposed to be the product of the units of the input. In this expression, that unit will be $\rm cm \cdot cm$ , which is occasionally written as $\rm cm^2$ .

$\rm 4.51 \; cm \times 3.6666 \; cm \approx 16.5\; \rm cm^2$ . (Rounded to three significant figures.)

7 0

3 years ago

Give the nuclear symbol (isotope symbol) for the isotope of bromine, Br, that contains 46 neutrons per atom.

Doss [256]

Bromine has 35 protons, and in this case 46 neutrons, so 35 + 46 = 81
Therefore, the symbol is (subscript 35)(superscript 81) Br.

5 0

3 years ago

When examining features on the ocean floor, like a volcano, how would it appear?

kogti [31]

The correct answer is 33% i tried it on a lesson.

8 0

3 years ago

One of the students in lab decided to use two fractionating columns (one on top of the other) instead of just one. How would thi

Andrews [41]

Answer:

See detailed explanation.

Explanation:

Hello there!

In this case, according to the given description, it turns out possible for us to infer that the second fractionating column on top of the first one will favor the light product, in this case hexane as it has the lowest boiling point and molar mass; in such a way, we can tell the following:

a) The separation between hexane and heptane will be increased as a purer hexane-rich product will be obtained on the top of the second column.

b) Will be increased as well, because the second column will remove more heptane.

c) Also, more pure heptane will be obtained on the bottom of the two columns, yet the most favored yield will be that of hexane.

All of the aforementioned is possible due to the fact that the second column will remove the amount of heptane that could not be removed on the top of the first column by taking the vapor-liquid equilibrium further from the first column's maximum separation, which is known as distillation sequences.

Regards!

8 0

3 years ago