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Inessa05 [86]
3 years ago
7

Acid rain can be destructive to both the natural environment and human-made structures. The equation below shows a reaction that

occurs that may lead to the formation of acid rain. 3NO2 + H2O mc025-1.jpg 2HNO3 + NO How many moles (precise to the nearest 0.01 mol) of nitric acid are produced from 300.00 mol of nitrogen dioxide?
Chemistry
2 answers:
alexandr1967 [171]3 years ago
8 0
The moles of nitric acid formed can be computed using the stoichiometric relation obtained from the given equation which indicates that for every 3 moles of nitrogen dioxide (NO2), 2 moles of nitric acid (HNO3) is formed. 300 moles of NO2 is then multiplied to 2 mol HNO3/ 3 mol NO2. The answer is 200 moles of nitric acid is produced from 300 moles of NO2. 
VLD [36.1K]3 years ago
4 0

Answer;

200.00 moles of nitric acid is produced

Explanation;

From the equation;

3NO2 + H2O → 2HNO3 + NO

The mole ratio of nitrogen (IV) oxide  and nitric acid is 3 is to 2;

Thus; for every 3 moles of nitrogen dioxide (NO2), 2 moles of nitric acid (HNO3) are formed. 

Therefore; 300 moles of NO2 will produce;

2 mol HNO3/ 3 mol NO2 (300) = 200 moles

Hence, 200 moles of nitric acid are produced from 300 moles of NO2. 

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you are exploring the properties of a piece of matter you cut it in half several times which property of matter changes
Lapatulllka [165]
Only Extensive properties of piece will be changed. i.e Mass, Volume, Length etc.
3 0
2 years ago
How many atoms are in 3.690 moles of oxygen
sweet [91]

1 mole of any substance contains Avogadro's number.  

So, 1 mole of O2= 6.023x10^23 molecules  

3 mole of O2= 6.023x10^23x3 molecules  

= 1.8069x10^24 molecules  

Each molecule of Oxygen has 2 atoms.  

therefore,  

1.8069x10^24 molecules= 1.8069x10^24 x 2 atoms  

= 3.6138x10^24 atoms.

4 0
3 years ago
mixture of N 2 And H2 Gases weighs 13.22 g and occupies a volume of 24.62 L at 300 K and 1.00 atm.Calculate the mass percent of
anygoal [31]

<u>Answer:</u> The mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of the gaseous mixture = 1.00 atm

V = Volume of the gaseous mixture = 24.62 L

n = number of moles of the gaseous mixture = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gaseous mixture = 300 K

Putting values in above equation, we get:

1.00atm\times 24.62L=n_{mix}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 300K\\\\n_{mix}=\frac{1.00\times 24.62}{0.0821\times 300}=0.9996mol

We are given:

Total mass of the mixture = 13.22 grams

Let the mass of nitrogen gas be 'x' grams and that of hydrogen gas be '(13.22 - x)' grams

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

<u>For nitrogen gas:</u>

Molar mass of nitrogen gas = 28 g/mol

\text{Moles of nitrogen gas}=\frac{x}{28}mol

<u>For hydrogen gas:</u>

Molar mass of hydrogen gas = 2 g/mol

\text{Moles of hydrogen gas}=\frac{(13.22-x)}{2}mol

Equating the moles of the individual gases to the moles of mixture:

0.9996=\frac{x}{28}+\frac{(13.22-x)}{2}\\\\x=12.084g

To calculate the mass percentage of substance in mixture we use the equation:

\text{Mass percent of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100

Mass of the mixture = 13.22 g

  • <u>For nitrogen gas:</u>

Mass of nitrogen gas = x = 12.084 g

Putting values in above equation, we get:

\text{Mass percent of nitrogen gas}=\frac{12.084g}{13.22g}\times 100=91.41\%

  • <u>For hydrogen gas:</u>

Mass of hydrogen gas = (13.22 - x) = (13.22 - 12.084) g = 1.136 g

Putting values in above equation, we get:

\text{Mass percent of hydrogen gas}=\frac{1.136g}{13.22g}\times 100=8.59\%

Hence, the mass percent of nitrogen gas and hydrogen gas is 91.41 % and 8.59 % respectively.

5 0
3 years ago
How to do 22.4 kg/L to kg/mL
emmainna [20.7K]
1 kg/L ----------- 0.001 kg/mL
22.4 kg/L ------- ??

22.4 x 0.001 / 1 => 0.0224 kg/mL
6 0
3 years ago
What is the mass of the hydrogen atoms in 1 mole of water
Katen [24]

<u>Answer:</u>

2.0158 grams

<u>Explantion:</u>

We are to find the mass of the hydrogen atoms in 1 mole of water.

We know that the formula of water is: H_2O

We can see, from the above mentioned formula, that water has 2 hydrpgen atoms.

From the periodic table, we get to know that Hydrogen has an atomic mass of 1.00794 grams.

As there are 2 atoms of hydrogen in water so 2 \times 1.00794 = 2.0158 grams is the answer

3 0
3 years ago
Read 2 more answers
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