For the derivative tests method, assume that the sphere is centered at the origin, and consider the
circular projection of the sphere onto the xy-plane. An inscribed rectangular box is uniquely determined
1
by the xy-coordinate of its corner in the first octant, so we can compute the z coordinate of this corner
by
x2+y2+z2=r2 =⇒z= r2−(x2+y2).
Then the volume of a box with this coordinate for the corner is given by
V = (2x)(2y)(2z) = 8xy r2 − (x2 + y2),
and we need only maximize this on the domain x2 + y2 ≤ r2. Notice that the volume is zero on the
boundary of this domain, so we need only consider critical points contained inside the domain in order
to carry this optimization out.
For the method of Lagrange multipliers, we optimize V(x,y,z) = 8xyz subject to the constraint
x2 + y2 + z2 = r2<span>. </span>
"Completing the square" is a step in the solution of quadratic equations. It can be accomplished without the guesswork or trial-and-error associated with methods like factoring, and it always leads to a solution. It is the method by which the quadratic formula is derived.
Eighteen trillion four hundred twenty nine billion fifty thousand
Answer:
See answer below
Step-by-step explanation:
For the first expression
3 x (x - 2) + 2 = 3 x^2 - 6 x + 2
evaluated at x= 4 we get: 26
and for x = 5 we get 47.
For the second expression
2 x^2 + 3 x - 18
we get the exact same values when doing the evaluation at these two points.
Based on those results, one may think the expressions may be equivalent, but they are not equivalent. Because at any other x-value, their results are different. See for example that for x = 0 the first one gives "2" while the second one gives -18.
Answer:
see below
Step-by-step explanation:
1. 0 = (r + 1)(r + 8)
Using Zero Product Property, r = -1, r = -8
2. h(r) = (r + 1)(r + 8)
= r² + 9r + 8
= (r + 9/2)² - 81/4 + 8
= (r + 4.5)² - 12.25 (Complete the square)
Vertex: (-4.5, -12.25)
